Answer:
c
Explanation:
protons are the atomic number which define an element
Here we have to calculate the number of moles of valuable propane can be prepared from 1.8 moles of carbon.
From 1.8 moles of carbon 0.3 moles of propane can be prepared by the reaction.
From 6 moles of carbon (C) 1 moles of valuable propane (C₃H₈) can be prepared.
Thus from 1.8 moles of C we can obtain 
×1.8 = 0.3 moles of the propane can be prepared.
Thus the amount of propane produced in this reaction is determined.
Answer:
2KHCO3+ H3PO4 arrow K2HPO4 + 2 H20 + 2C02
Explanation:
2KHCO3+ H3PO4 arrow K2HPO4 + 2 H20 + 2C02
Start with the Ks. Don't start on the right. Just balance the Ks on the left. The reason is that the CO3 is going to break down as well.
2KHCO3+ H3PO4 arrow K2HPO4 + H20 + C02
Leave the PO4 alone. Now look at the Hs that are on the right. There are 5 on the left. Leave the K2HPO4 alone. If you put a 2 in front of tthe H2O then you have a total of 5 Hs on the right.
2KHCO3+ H3PO4 arrow K2HPO4 + 2H20 + C02
There are 2 carbons on the left. You need 2 on the right.
2KHCO3+ H3PO4 arrow K2HPO4 + 2H20 + 2C02
That should do it.
Let's make a table to show balance.
Species K H C PO4- O
Left 2 5 2 1 6 from CO3^(2-)
Right 2 5 2 1 6 from H2O/CO2
Animal breeding is the process of selective mating of animals with desirable genetic traits, to maintain these traits in future generations.
Answer:
The equilibrium will shift to the right
Explanation:
The chemical equilibrium represents a balance between direct and inverse reactions.
The Le Chatelier Principle states that variations in experimental conditions can alter this balance and displace the equilibrium position, causing more or less of the desired product to form. And in this way the system evolves in the opposite direction so as to counteract the effects of such disturbance.
The variation of one or more of the following factors are those that can alter the equilibrium condition:
-
Temperature
- The pressure
- The volume
- The concentration of reactants or products
In this case:
NaOH produces OH⁻ ions. OH⁻ ion uses up H₃O⁺ through the reaction:
H₃O⁺ + OH⁻ → 2 H₂O
According to the Le Chatelier principle, the addition of NaOH consumes one of the products, decreasing its concentration. Therefore, to balance the reaction, <u><em>the equilibrium will shift to the right</em></u> in order to counteract the effect that disturbed it and recover the equilibrium state.
