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elena-14-01-66 [18.8K]
3 years ago
6

A 5.00 cm^3 sample of gold has a mass of 96.5 g. Calculate the density of gold.

Chemistry
1 answer:
Sholpan [36]3 years ago
8 0

Answer:

\boxed {\boxed {\sf 19.3 \ g/cm^3}}

Explanation:

We are asked to calculate the density of gold. The density of a substance is its mass per unit volume. It is calculated using the following formula.

\rho= \frac{m}{v}

The mass of the sample is 96.5 grams. The volume of the sample is 5.00 cubic centimeters.

  • m= 96.5 g
  • v= 5.00 cm³

Substitute the values into the formula.

\rho= \frac{ 96.5 \ g}{5.00 \ cm^3}

Divide.

\rho= 19.3 \ g/cm^3

The density of gold is <u>19.3 grams per cubic centimeter.</u>

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Answer:

a. pka = 3,73.

b. pkb = 10,27.

Explanation:

a. Supposing the chemical formula of X-281 is HX, the dissociation in water is:

HX + H₂O ⇄ H₃O⁺ + X⁻

Where ka is defined as:

ka = \frac{[H_3O^+][X^-]}{[HX]}

In equilibrium, molar concentrations are:

[HX] = 0,089M - x

[H₃O⁺] = x

[X⁻] = x

pH is defined as -log[H₃O⁺]], thus, [H₃O⁺] is:

[H_3O^+]} = 10^{-2,40}

[H₃O⁺] = <em>0,004M</em>

Thus:

[X⁻] = 0,004M

And:

[HX] = 0,089M - 0,004M = <em>0,085M</em>

ka = \frac{[0,004][0,004]}{[0,085]}

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pkb = 14,00 - 3,73

<em>pkb = 10,27</em>

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4 0
3 years ago
An object has a gravitational potential energy that is 800 Joules. Its
olya-2409 [2.1K]

Answer:

36.28 kg

Explanation:

Given data:

Gravitational potential energy of object = 800 J

Height from ground = 2.245 m

Mass of object = ?

Solution:

Formula:

P.E = mgh

g =acceleration due to gravity =  9.8 m/s²

by putting values,

800 J = m× 9.8 m/s² ×2.25 m

J = kgm²/s²

800 kgm²/s² = m× 22.05 m²/s²

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2 years ago
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3 years ago
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mrs_skeptik [129]

Mass of SiC = 2 g

<h3>Further explanation</h3>

Given

Reaction

SiO₂(s) + 3C(s) → SiC(s) + 2CO(g)

3.00 g of SiO₂

4.50 g of C

Required

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3 0
2 years ago
EXPLAIN How would you explain the difference between single displacement and
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Explanation:

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3 0
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