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3 years ago

A 5.00 cm^3 sample of gold has a mass of 96.5 g. Calculate the density of gold.

Chemistry

1 answer:

Sholpan [36]3 years ago

8 0

Answer:

$\boxed {\boxed {\sf 19.3 \ g/cm^3}}$

Explanation:

We are asked to calculate the density of gold. The density of a substance is its mass per unit volume. It is calculated using the following formula.

$\rho= \frac{m}{v}$

The mass of the sample is 96.5 grams. The volume of the sample is 5.00 cubic centimeters.

m= 96.5 g
v= 5.00 cm³

Substitute the values into the formula.

$\rho= \frac{ 96.5 \ g}{5.00 \ cm^3}$

Divide.

$\rho= 19.3 \ g/cm^3$

The density of gold is 19.3 grams per cubic centimeter.

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If 125g of KClO3 is heated, what is the total mass of the products?

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Mass of KClO₃ = 125g

Unknown:

Total mass of the products = ?

When KClO₃ is heated, it thermally decomposes to KCl and O₂ according to the chemical equation below;

2KClO₃ → 2KCl + 3O₂

All chemical equations obeys the law of conservation of matter and with this regard, we know that the amount of reactants used is the same as that of the product.

The total mass of the products must give us 125g according to this law of conservation of matter.

Now to find the masses of each product,

Find the number of moles of the given reactant:

Number of moles = $\frac{mass}{molar mass}$

molar mass of KClO₃ = 39 + 35.5 + 3(16) = 122.5g/mol

So number of moles of KClO₃ = $\frac{125}{122.5}$ = 1.02moles

2. Now, using this number of moles, find the number of moles of the products using this value;

2 moles of KClO₃ produced 2 moles of KCl

1.02 moles of KClO₃ will also produce 1.02moles of KCl

2 moles of KClO₃ produced 3 moles of O₂

1.02 moles of KClO₃ will produce $\frac{1.02 x 3} {2}$ mole = 1.53 moles of O₂

3. Now find the masses of each product;

Mass = number of moles x molar mass

molar mass of KCl = 39 + 35.5 = 74.5g/mol

molar mass of O₂ = 16 x 2 = 32g/mol

Mass of KCl = 74.5 x 1.02 = 75.99g

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Total mass of products = mass of KCl + Mass of O₂ = 75.99g + 48.96g

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This value is approximately the same as that of mass of KClO₃

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