A total of 25.0 mL of 0.150 M potassium hydroxide (KOH) was required to neutralize 15.0 mL of sulfuric acid (H2SO4) of unknown c
1 answer:
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Answer:
The answer is
<h2>1479.60 mL</h2>Explanation:
In order to calculate the volume needed we use the formula
where
C1 is the concentration of the stock solution
V1 is the volume of the stock solution
C2 is the concentration of the diluted solution
V2 is the volume of thevdiluted solution
From the question
C1 = 1.45 M
V1 = 25 mL
C2 = 0.0245 M
So we have
We have the final answer as
<h3>1479.60 mL</h3>Hope this helps you