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4 years ago

What is activation energy?

Chemistry

1 answer:

balu736 [363]4 years ago

8 0

Answer:

Explanation:

energy needed to get a reaction started

hope this helps. good luck :)

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An aqueous HCL solution has a proton concentration equal to 6.00 mol/L. The HCL concentration in this solution is ————M.

Harman [31]

Answer:

HCl conc.= 6.0mol/L

Explanation:

From the dissociation of HCl= 1 mole H+ and 1mol Cl-, which is equivalent stoichiometrically in concentration to that of 1 mol HCl,

4 0

3 years ago

Acetylene gas (C2H2) is used in welding torches. When it reacts with oxygen, it produces

Vikki [24]

Mass C₂H₂ needed : 22.165 g

<h3>Further explanation</h3>

Reaction

2C₂H₂+ 5O₂ ⇒ 4CO₂ + 2H₂O

75.0 grams of CO₂ , mol CO₂ (MW=44 g/mol) :

$\tt \dfrac{75}{44}=1.705$

mol C₂H₂ :

$\tt \dfrac{2}{4}\times 1.705=0.8525$

mass C₂H₂ (MW=26 g/mol) :

$\tt 0.8525\times 26=22.165~g$

8 0

3 years ago

Covert 1.57 x 10^14 nm= ___m

LekaFEV [45]

Answer:

1.57 x 10⁷m

Explanation:

Given quantity is;

1.57 x 10¹⁴nm

Now;

1 nm = 10⁻⁹

So, let us convert this given quantity;

1 nm = 10⁻⁹

1.57 x 10¹⁴nm will give 1.57 x 10¹⁴ x 10⁻⁹ = 1.57 x 10⁷m

7 0

3 years ago

Given the density of iron (Fe) is 7.87 g/cm3, determine the mass of iron (in grams) in a rectangle block with the dimensions of

guapka [62]

Answer:

$m=14,105.71 g Fe$

Explanation:

Hello,

In this case, the first step is to compute the volume of the block considering the length, height and width:

$V=L \times W \times H =12.5 in\times 3.50 in \times 2.50 in =109.375 in^3$

Then, we compute the volume in cubic centimetres:

$V=109.375in^3\times \frac{16.3871 cm^3}{1in^3} =1792.34cm^3$

Finally, as the density is given by:

$\rho =\frac{m}{V}$

We solve for the mass:

$m=\rho \times V= 7.87\frac{g}{cm^3} \times 1792.34 cm^3\\\\m=14,105.71 g Fe$

Best regards.

8 0

3 years ago

How many moles of HCl can be produced from 0.226 g of SOCl2? SOCl2 + H2O ----> SO2 + 2HCl

jeka94

Answer:

3.80*10⁻³ moles of HCl can be produced from 0.226 g of SOCl₂

Explanation:

The balanced reaction is:

SOCl₂ + H₂O ----> SO₂ + 2 HCl

By stoichiometry of the reaction they react and produce:

SOCl₂: 1 mole
H₂O: 1 mole
SO₂: 1 mole
HCl: 2 mole

Being:

S: 32 g/mole
O: 16 g/mole
Cl: 35.45 g/mole
H: 1 g/mole

the molar mass of the compounds participating in the reaction is:

SOCl₂: 32 g/mole + 16 g/mole + 2*35.45 g/mole= 118.9 g/mole
H₂O: 2*1 g/mole + 16 g/mole= 18 g/mole
SO₂: 32 g/mole + 2*16 g/mole= 64 g/mole
HCl: 1 g/mole + 35.45 g/mole= 36.45 g/mole

Then, by stoichiometry of the reaction, the following amounts of mass react and are produced:

SOCl₂: 1 mole* 118.9 g/mole= 118.9 g
H₂O: 1 mole* 18 g/mole= 18 g
SO₂: 1 mole* 64 g/mole= 64 g
HCl: 2 mole* 36.45 g/mole= 72.9 g

Then the following rule of three can be applied: if by stoichiometry of the reaction 118.9 grams of SOCl₂ produce 2 moles of HCl, 0.226 grams of SOCl₂ how many moles of HCl do they produce?

$moles of HCl=\frac{0.226 grams of SOCl_{2}*2 mole of HCl }{118.9 grams of SOCl_{2} }$

moles of HCl= 3.80*10⁻³

<u><em>3.80*10⁻³ moles of HCl can be produced from 0.226 g of SOCl₂</em></u>

7 0

4 years ago