What is the answer for this math problem 2 k -13k + c

Suppose that for a company manufacturing calculators, the cost, revenue, and profit equations are given by Start 1 By 3 Matrix

Nesterboy [21]

Answer:

Cost is Increasing at a rate of 20,000 per week
Revenue is decreasing at a rate of 100,000 per week
Profit is decreasing at a rate of 120,000 per week

Step-by-step explanation:

The cost, revenue, and profit equations for a company manufacturing calculators are given below:

Cost, C=90000+40x
Revenue, $R=200x-\frac{x^2}{20}$
Profit = R - C

$\frac{dx}{dt} =500\\$ When Production output x=4000

Change in Cost

Cost, C=90000+40x

$\frac{dC}{dt} =40\frac{dx}{dt}=40*500\\\frac{dC}{dt}=20,000$

Change in Revenue

$\frac{dR}{dt} =200\frac{dx}{dt}-\frac{x}{10}\frac{dx}{dt}\\=200*500-\frac{4000}{10}*500\\\frac{dR}{dt} =-100,000$

Change in Profit

$\frac{dP}{dt} =\frac{dR}{dt}-\frac{dC}{dt}\\=-100,000-20,000\\\frac{dP}{dt}=-120,000$

Therefore, when production output is 4000 and increasing at a rate of 500 calculators per week,

Cost is Increasing at a rate of 20,000 per week
Revenue is decreasing at a rate of 100,000 per week
Profit is decreasing at a rate of 120,000 per week

5 0

3 years ago

Please help ASAP 20 pts + brainliest to right/best answer

hram777 [196]

Answer:

the answer is C

Step-by-step explanation:

The equation is just asking for you to subtract the entire function of f from the function of G. This directly translates to (x^2) - (3x +5) which cannot be simplified further than the subtraction sign. You end with x^2 - 3x -5

Hope this helps

4 0

3 years ago

The temperature dropped 18 degrees from 6:00 P.M. to midnight. If the temperature at midnight was 2°F, what

vazorg [7]

Answer:

x - 18°F = 2°F

x = 20°F

Step-by-step explanation:

First, write the equation with the information you know. It dropped 18°F from 6 to midnight, and by midnight the temperature was 2°F

Your equation should look like this: x - 18°F = 2°F

Move the constant to the right hand side and change it's sign:

x = 2°F + 18°F

Add the numbers to get x = 20°F

Hope this helped!

6 0

3 years ago

John runs to the market and comes back in 15 minutes. His speed on the way to the market is 5m/s and his speed on the way back i

katen-ka-za [31]

Answer:

The distance to the market is 2000 m

Step-by-step explanation:

∵ John runs to the market and comes back in 15 minutes

→ Change the min. to the sec. because the unit of his speed is m/s

∵ 1 minute = 60 seconds

∴ 15 minutes = 15 × 60 = 900 seconds

→ Assume that t1 is his time to the market and t2 is his time from

the market

∵ t1 + t2 = 15 minutes

∴ t1 + t2 = 900 ⇒ (1)

→ Assume that the distance to the market is d

∵ His speed on the way to the market is 5m/s

∵ Time = Distance ÷ Speed

∴ t1 = d ÷ 5 ⇒ (1 ÷ 5 = 0.2)

∴ t1 = 0.2d ⇒ (2)

∵ His speed on the way back is 4m/s

∴ t2 = d ÷ 4 ⇒ (1 ÷ 4 = 0.25)

∴ t2 = 0.25d ⇒ (3)

→ Substitute (2) and (3) in (1)

∵ 0.2d + 0.25d = 900

∴ 0.45d = 900

→ Divide both sides by 0.45

∴ d = 2000 m

∴ The distance to the market = 2000 m

8 0

3 years ago

$5 box of cereal: 40% discount?

REY [17]

Uh sure what type of cereal?

4 0

3 years ago