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OlgaM077 [116]
3 years ago
11

What is the answer for this math problem 2 k -13k + c

Mathematics
1 answer:
lozanna [386]3 years ago
6 0

Answer: c-11k

Step-by-step explanation:

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£150 is invested at 5% compound interest for 2 years. How much will be in the account at the end of the investment?
morpeh [17]

Answer:

165

Step-by-step explanation:

5% of 150 british pounds = 7.5 British pounds

2 years = 7.5 BS per year

7.5 + 7.5

= 15 british pounds

15 british pounds + 150 british pounds =

165 british pounds

7 0
2 years ago
Are the given lines parallel? Explain <br> X=-1, and y=2
german
No they would be intersecting. x=-1 is a vertical line down the x axis on -1. y=2 is a horizontal line at 2 on the y axis.
5 0
3 years ago
Read 2 more answers
An action movie production team needs glass spheres to hold a green liquid that looks like an explosive. If all of the available
Sergeu [11.5K]
Since all the volume of the liquid will be contained by all 30 spheres then,
30 V = 3392.92

where V is the volume of each sphere
Solving for V
V = 113.0973

The formula for the volume of the sphere is:
V = (4/3) π r³

Since diameter, D = 2r
V = (4/3) π (D/2)³
V = (4/3) π (1/8) D³
V = (1/6) π D³

Since V = 113.0937
113.0937 = (1/6) π D³
D = 6

<span>Therefore, the diameter is 6 inches </span>
5 0
3 years ago
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Determine the current through each of the LEDs in the circuits below. Which LED will be
Anika [276]

a. I = 6. 1 × 10^-4 A

b. I = 2. 6 × 10^-3 A

c. I = 0. 04 A

The LED which would glow brightest is LED C with the greatest current and voltage

The LED which would be the most dim is LED B with low voltage and consequently low current.

<h3>How to determine the current</h3>

The formula for finding current

I = V/R

Where v = voltage

R = resistance

A. V = 12V

R = 4. 7 + 15 = 19. 7 kΩ = 19700 Ω in series

I = \frac{12}{19700}

I = 6. 1 × 10^-4 A

B. V = 9V

R = 4. 7 + 1 = 4. 7 kΩ = 4700Ω in series

I = \frac{12}{4700}

I = 2. 6 × 10^-3 A

C.  V=  12V

1/R = \frac{1}{750} + \frac{1}{1200} + \frac{1}{950 } = 3. 22 × 10^-3

R = \frac{1}{3. 22 * 10 ^-3} = 310. 56 Ω

I = \frac{12}{310. 56}

I = 0. 04 A

It is important to note that the brightness of a bulb depends on both current and voltage depending on whether the bulb it is in parallel or series.

The LED which would glow brightest is LED C with the greatest current and voltage

The LED which would be the most dim is LED B with low voltage and consequently low current.

Learn more about Ohms law here:

brainly.com/question/14296509

#SPJ1

8 0
2 years ago
Which expression shows the result of applying the distributive property to 9(2+5m)9(2+5m)
Alik [6]

Answer:the answer is 18+45m


Step-by-step explanation:


6 0
3 years ago
Read 2 more answers
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