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Eva8 [605]
3 years ago
13

Find the equation of a line perpendicular to y-3x=-8 that passes through the point (3,2). Answer in slope-intercept form

Mathematics
2 answers:
Zielflug [23.3K]3 years ago
8 0
Y - 3x = -8
y = 3x - 8...slope here is 3. A perpendicular line will have a negative reciprocal slope. All that means is " flip " the slope and change the sign. So the slope we need is -1/3.

y = mx + b
slope(m) = -1/3
(3,2)...x = 3 and y = 2
now we sub and find b, the y int
2 = -1/3(3) + b
2 = -1 + b
2 + 1 = b
3 = b

so ur perpendicular equation is : y = -1/3x + 3
Andrew [12]3 years ago
4 0
Perpendicular to y - 3x = -8 
Change that to slope form 
y = 3x - 8

Perpendicular to that means the slopes would equal to -1 when multiplied 

3x = -1
Thus the slope of the other equation would be -1/3

y - y1 = m(x - x1)
where m is the slope 
y - 2 = -1/3(x - 3)
y - 2 = (-1/3)x - 1 
y = (-1/3)x + 1
That's the equation 
hope it helps. 
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What is the closed linear form for this sequence given a1 = 0.3 and an + 1 = an + 0.75?
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Answer:

The closed linear form of the given sequence is a_{n}=0.75n-0.45

Step-by-step explanation:

Given that the first term a_{1}=0.3 and a_{n+1}=a_{n}+0.75

To find the closed linear form for the given sequence

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a_{n}=a_{1}+(n - 1)d  (where d is the common difference)

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We can substitute these values in a_{n}=a_{1}+(n - 1)d

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