-5(p+11) help please

Estimate the sum 5.89 7 1/12

Agata [3.3K]

Answer:

13

Step-by-step explanation:

Estimate 5.89 to 6.

5.89 ≈ 6

Estinate 7 1/12 to 7.

7.083 ≈ 7

Estimate the sum.

7 + 6 = 13

3 0

3 years ago

Read 2 more answers

Find the values of x and y for which the lines are parallel.

bearhunter [10]

The answer: " x = 68, y = 72 " .
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Explanation:
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46 + (x - 3) + (y - 3) = 180 .

46 + 1(x - 3) + 1(y-3) = 180 .

46 + 1x - 3 + 1y - 3 = 180 .

46 - 3 - 3 + 1x + 1y = 180 .

40 + x + y = 180 ;

Subtract "40" from EACH SIDE of the equation:
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40 + x + y - 40 = 180 - 40 ;

to get:

x + y = 140 ;
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Now:
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65 = (x - 3) ;

↔ x - 3 = 65 ;

Add "3" to EACH SIDE of the equation;

    x - 3 + 3 = 65 + 3 ;

to get:

           x = 68 .
______________________________
Now:

Since: "x + y = 140" ;

Let us plug in our known value, "68" ; for "x" ;

to solve for "y" ;
__________________________________
   x + y = 140 ;

  68 + y = 140 ;

↔ y + 68 = 140 ;

Subtract "68" from EACH SIDE of the equation; to isolate "y" on one side of the equation; and to solve for "y" ;
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   y + 68 - 68 = 140 = 68 ;

                  y = 72 .
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So, solve for "x" and "y".

x = 68, y = 72 .
_______________________________________________

5 0

3 years ago

Colin has a pad with x pieces of paper on it. For his first class, he wrote on 5 fewer than half of the pieces of paper in the p

PIT_PIT [208]

Answer:

Colin has 8 sheets left for his third class.

Step-by-step explanation:

Given that:

Total Number of pieces of papers = $x$

Number of pieces of papers used for 1st class = 5 fewer than half of the pieces in the pad

Writing the equation:

$\text{Number of pieces of papers used for 1st class =} \dfrac{x}{2} -5 ...... (1)$

Also, Given that number of pieces of papers used for the 2nd class are 2 more than that of papers used in the 1st class.

$\text{Number of pieces of papers used for 2nd class =} \dfrac{x}{2} -5+2 = \dfrac{x}2 -3 ...... (2)$

Now, number of pieces of papers left for the third class = Total number of pieces of papers in the pad - Number of pieces of papers used in the first class - Number of pieces of papers used in the first class

$\text{number of pieces of papers left for the third class = }x-(\dfrac{x}{2}-5)-(\dfrac{x}{2}-3)\\\Rightarrow x-\dfrac{x}2-\dfrac{x}2+5+3\\\Rightarrow x-x+5+3\\\Rightarrow 8$

So, the answer is:

Colin has 8 sheets left for his third class.

5 0

3 years ago

A 2-column table with 4 rows. Column 1 is labeled Size of Container with entries 12 ounces, 16.3 ounces, 28 ounces, 64 ounces. C

Jobisdone [24]

Answer:

12 oz: $0.35 per oz

16.3 oz: $0.38 per oz

28 oz: $0.30 per oz

64 oz: $0.33 per oz

Which size is the best deal?

28 oz

Step-by-step explanation: it gave me the right answer after.

5 0

3 years ago

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A jet climbs at a steady rate at an angle of inclination of 0.5 degree during game off what will its he height be after a 2.2 km

Aneli [31]

A right triangle will be formed with 2.2 km as the hypotenuse, 0.5 degrees as the angle, and an unknown height (see attachment).

Recall the trigonmetric ratios sine, cosine, and tangent that can be used for right triangles.
Sinθ = opposite side/hypotenuse
Cosθ = adjacent side/hypotenuse
tanθ = opposite side / adjacent side
θ (theta) refers to the angle (not the right angle). In this case, θ is the given angle of 0.5°.

In this problem, you will use sine because there is a side opposite to the angle (the unknown side h) and the hypotenuse, and sine relates those two sides.

Let the variable h represent the unknown opposite side, the height.
sin(0.5°) = h / (2.2km)
h = (2.2km)sin(0.5°)
h = 0.019 km

Hope I helped! If you have questions on any of the steps, please comment below.

3 0

3 years ago