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mel-nik [20]
3 years ago
12

PLS HELP ME I ONLY HAVE 5 MINUTES PLS

Mathematics
1 answer:
Viefleur [7K]3 years ago
3 0

Answer: 71 ft

i hope its the right answeer, do well

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A pilot took 1/2 hours to complete his 1/3 pf his ttip how much longer will it take him to complete his trip?
Norma-Jean [14]

Answer:

1.5 hours

Step-by-step explanation:

1/2 + 1/2 + 1/2 =1.5

7 0
3 years ago
A certain brand of flood lamps has a lifetime that is normally distributed with a mean of 3,750 hours and a standard deviation o
vesna_86 [32]
Given that mean=3750 hours and standard deviation is 300:
Then:
<span>a. The probability that a lamp will last for more than 4,000 hours?
P(x>4000)=1-P(x<4000)
but
P(x<4000)=P(z<Z)
where:
z=(x-</span>μ)/σ
z=(4000-3750)/300
z=0.833333
thus
P(x<4000)=P(z<0.8333)=0.7967
thus
P(x>4000)=1-0.7967=0.2033

<span>b.What is the probability that a lamp will last less than 3,000 hours?
P(x<3000)=P(z<Z)
Z=(3000-3750)/300
z=-2.5
thus
P(x<3000)=P(z<-2.5)=0.0062

c. </span><span>.What lifetime should the manufacturer advertise for these lamps in order that only 4% of the lamps will burn out before the advertised lifetime?
the life time will be found as follows:
let the value be x
the value of z corresponding to 0.04 is z=-2.65
thus
using the formula for z-score:
-2.65=(x-3750)/300
solving for x we get:
-750=x-3750
x=-750+3750
x=3000</span>
7 0
4 years ago
How do I solve for n?​
Finger [1]
Simple just do normal simple algebra:)
3 0
3 years ago
Simplify the expression (5 3i) (4-4i) a. 8i b. 9-i c. 9 i d. 9-7i
poizon [28]
The expression will be d. 9-7i
8 0
3 years ago
The director of the library calculates that 29% of the library's collection is checked out. If the director is right, what is th
marusya05 [52]

Answer:

The probability that the proportion of books checked out in a sample of 412 books would differ from the population proportion by less than 4% is P=0.9255.

Step-by-step explanation:

The population's proportion is \pi=0.29

If we take a sample of 412 books (n=412), we have a standard deviation of the sampling distribution of:

\sigma_M=\sqrt{\frac{\pi(1-\pi)}{n}}=\sqrt{\frac{0.29*0.71}{412}}=\sqrt{0.0005} =0.0224

We have to calculate the probabilty that the sample proportion will be between 0.25 and 0.33.

z_1=(0.25-0.29)/0.0224=-0.04/0.0224=-1.7857\\\\z_2=1.7857\\\\\\P(0.25

8 0
4 years ago
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