Jim 19, 700g sand in his sandbox. Brings home another 6,300g

The access code for a garage door consists of three digits. Each digit can be any number from 1 through 5, and each digit can b

Papessa [141]

Answer:

(a) 125

$(b) \dfrac{1}{125}$

$(c) \dfrac{124}{125}$

Step-by-step explanation:

We are given that access code consists of 3 digits.

Each digit can be any digit through 1 to 5 and can be repeated.

Now, this problem is equivalent to the problem that we have to find:

The number of 3 digit numbers that can be formed using the digits 1 to 5 with repetition allowed.

(a) We have 3 places here, unit's, ten's and hundred's places respectively and each of the 3 places have 5 possibilities (any digit allowed with repetition).

So, total number of access codes possible:

$5\times 5 \times 5 = 125$

(b) Suppose, an access code is randomly selected, what is the probability that it will be correct.

Formula for probability of an event E can be observed as:

$P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}$

Here, only 1 code is correct, so

Number of favorable cases = 1

Total number of cases = 125

So, required probability:

$P(E) = \dfrac{1}{125}$

(c) Probability of not selecting the correct access code on first time:

$P(\overline E) = 1-P(E)\\\Rightarrow P(\overline E) = 1-\dfrac{1}{125}\\\Rightarrow P(\overline E) = \dfrac{125-1}{125}\\\Rightarrow P(\overline E) = \dfrac{124}{125}$

So, the answers are:

(a) 125

$(b) \dfrac{1}{125}$

$(c) \dfrac{124}{125}$

7 0

3 years ago

suppose the population of a certain city has been doubling every 30 years and the population was 48,000 in 1900. what will the p

Brilliant_brown [7]

Answer:

768000

Step-by-step explanation:

From 1900 to 2020 = 120 means that it doubles 4 times ( once every 30 years)

=> 48000 * 2 ^ 4 = 768000

3 0

2 years ago

Six more than a number can be written as which variable expression

Firdavs [7]

N+6 would be my guess.

5 0

3 years ago

Pleaseee i need some help on these 3 questions

Zepler [3.9K]

Answer:

a) the product is equal to 953.

b) the product is greater than 443.

c) the product is greater than 181.

Step-by-step explanation:

a) 953 × 63/63 = 953

Therefore, the product is equal to 953.

b) 443 × 86/79 = 482.25

Therefore, the product is greater than 443.

c) 181 × 30/28 = 193.93

Therefore, the product is greater than 181.

Hope this helps =)

6 0

2 years ago

Identify the GCF of 6x2y2 − 8xy2 + 10xy3. 6x2y2 2x2y 2xy2 6xy2

sattari [20]

First find GCF of the numbers:-

GCF of 2, 6 and 8 = 2
GCF od x^2 x and x is x
GCF of y^2, y^2 and y^3 is y^2

so the answer is 2xy^2

The third choice.

3 0

3 years ago

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