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djyliett [7]
3 years ago
9

What is measured by the change in velocity of a moving object?

Physics
2 answers:
dolphi86 [110]3 years ago
7 0
Acceleration is the change of velocity (speed) or direction.
IrinaVladis [17]3 years ago
4 0

Answer:

acceleration is measured

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A transformer connected to a 120-V (rms) ac line is to supply 12,500 V (rms) for a neon sign. To reduce shock hazard, a fuse is
Tamiku [17]

Answer:

a) 104

b) 106

c) 884 mA

Explanation:

The ratio of the transformer is given by:

N=\frac{V_{out}}{V_{in}}=\frac{12500V}{120V}=104

We need to know the current in the primary in order to obtain the power applied.

I_1=I_2*N=8.50mA*104=884mA\\\\P=I*V=884*10^{-3}A*120V=106W\\

The current rating of the fuse is the current on the primary, 884mA as we calculated before in order to obtain the power.

4 0
3 years ago
How are energy and distance up the ramp related
AfilCa [17]
I don't exactly understand the question but I'll try my best to answer it and help you. You need energy in order to go up the ramp and cover the distance. I hope this helps! :)
8 0
3 years ago
An emu moving with constant acceleration covers the distance between two points that are 92 m
nasty-shy [4]

Answer:

a) V_{o}=14.30 m/s

b) a=-0.046 m/s^{2}

Explanation:

The complete question is written below:

An emu moving with constant acceleration covers the distance between two points that are 92 m  apart in 6.5s. Its speed as it passes the second point is 14 m/s. What are (a) its speed at the first point and (b) its acceleration?

Since we are talking about constant acceleration, we can use the following equations:

d=x-x_{o}=(\frac{V_{o}-V}{2})t (1)

V=V_{o}+at (2)

Where:

d=92 m is the distance between the two points

V_{o} is the velocity of the emu at the first point

V=14 m/s is the velocity of the emu at the second point

t=6.5 s is the time it takes to the emu to cover the distance d

a is the emu's constant acceleration

Knowing this, let's begin with the answers:

<h2>a) Speed at the first point</h2>

In this situation wi will use equation (1):

d=(\frac{V_{o}-V}{2})t (1)

Finding V_{o}:

V_{o}=\frac{2d}{t}-V (3)

V_{o}=\frac{2(92 m)}{6.5 s}-14 m/s (4)

V_{o}=14.30 m/s (5)

<h2>b) Emu's acceleration</h2>

Now we will substitute (5) in equation (2):

14 m/s=14.30 m/s+a(6.5 s) (6)

Finding a:

a=-0.046 m/s^{2} (7) This means the emu is decreasing its speed at a constant rate.

8 0
4 years ago
Distance between bholu and golu house house 9 km . bholu has to attend golu birthday party at 7am . he started from his home at
navik [9.2K]
For the rest 3 km


Bholu need to run in 5 minutes so


He need to 3 × 1000 / 5 × 60 m/s

3000/ 300 = 10 m/s


So , his speed should be 1 m/s to reach in 5 minute



mark as brainliest 5 star
6 0
4 years ago
Read 2 more answers
An unfortunate 18 kg monkey falls from a 40 m tall tree. What is the monkeys final velocity just befor he impacts the ground.? a
zalisa [80]
The correct answer is c) 28 m/s.
Let's find the step-by-step solution. The motion of the monkey is an uniformly accelerated motion, with acceleration equal to g=9.81 m/s^2. The initial velocity of the monkey is zero, while the distance covered is S=40 m. Therefore, we can use the following relationship to find vf, the final velocity of the monkey:
2aS=v_f^2-v_i^2=v_f^2
from which
v_f= \sqrt{2aS}= \sqrt{2\cdot 9.81 m/s^2 \cdot 40 m}=28 m/s
5 0
3 years ago
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