2x²-10xy+3xy-15y²
Add like terms.
2x²+ (-10xy+3xy) -15y²
Simplify.
2x² + (-7xy) - 15y²
Rearrange the equation.
2x²-15y²-7xy
~Hope I helped~
Answer:
w ≥ 6
l ≥ 11
Step-by-step explanation:
The perimeter of a rectangle is equal to P = 2l+2w where l=length and w=width. Here the length is 5 feet longer than the width or 5+w. This means the width is w. Substitute P = 34, l=5+w and w into the perimeter equation. Then solve for w.
34 ≤ 2*(5+w) + 2w
34 ≤ 10+2w+2w
34 ≤ 10+4w
24 ≤ 4w
6 ≤ w
This means the width must be at least 6 so the solution is w ≥ 6.
To find the length substitute 6 into l ≤ 5+w.
l ≤ 5 + 6
l ≤ 11
The length is l ≥ 11.
Measures of height
width does not matter
Answer:5/12 (Decimal: 0.416667)
Step-by-step explanation:
