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2 years ago

What is X in this equation?

Mathematics

1 answer:

oee [108]2 years ago

8 0

Answer:

B) 44

Step-by-step explanation:

x + 54 + 82 = 180

x + 136 = 180

x = 180 - 136

x = 44

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Simplify (5x - 7y) - ( x + 3y)

ruslelena [56]

This equation simplified is: $14x - 10y$

4 0

3 years ago

JT = 5x+ 8<br> CT = 70, and<br> CJ = 7x + 2<br> Find JT

defon

Answer:33

Step-by-step explanation: took one for the team

8 0

3 years ago

Can someone please write the points in a notebook please I really need help

nordsb [41]

Answer:

Step-by-step explanation:

8 0

3 years ago

Find a linear second-order differential equation f(x, y, y', y'') = 0 for which y = c1x + c2x3 is a two-parameter family of solu

Alisiya [41]

Let $y=C_1x+C_2x^3=C_1y_1+C_2y_2$ . Then $y_1$ and $y_2$ are two fundamental, linearly independent solution that satisfy

$f(x,y_1,{y_1}',{y_1}'')=0$
$f(x,y_2,{y_2}',{y_2}'')=0$

Note that ${y_1}'=1$ , so that $x{y_1}'-y_1=0$ . Adding $y''$ doesn't change this, since ${y_1}''=0$ .

So if we suppose

$f(x,y,y',y'')=y''+xy'-y=0$

then substituting $y=y_2$ would give

$6x+x(3x^2)-x^3=6x+2x^3\neq0$

To make sure everything cancels out, multiply the second degree term by $-\dfrac{x^2}3$ , so that

$f(x,y,y',y'')=-\dfrac{x^2}3y''+xy'-y$

Then if $y=y_1+y_2$ , we get

$-\dfrac{x^2}3(0+6x)+x(1+3x^2)-(x+x^3)=-2x^3+x+3x^3-x-x^3=0$

as desired. So one possible ODE would be

$-\dfrac{x^2}3y''+xy'-y=0\iff x^2y''-3xy'+3y=0$

(See "Euler-Cauchy equation" for more info)

6 0

3 years ago

FOCUS ON HIGHER ORDER THINKING Work Area Katie said, "Negative numbers are integers." What was Explain the Error her error?

Sav [38]

Step-by-step explanation:

Consider the provided information.

Integers: Integers are the set of whole number and the negatives of the natural numbers, i.e, … ,-2, -1, 0, 1, 2,...

Rational number: A number is said to be rational, if it is in the form of p/q. Where p and q are integer and denominator is not equal to 0.The decimal expansion of rational numbers may terminate or become periodic.

Irrational number: A number is irrational if it cannot be expressed be expressed by dividing two integers. The decimal expansion of Irrational numbers are neither terminate nor periodic.

Now consider the provided statement "Negative numbers are integers."

The statement is incorrect as all negative numbers are not integers they might be rational number or irrational numbers.

For example: -2.5 is a negative number but it is not an integer. The number is a rational number.

Hence, her statement is incorrect.

She can say that all negative whole numbers are integers.

6 0

3 years ago