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Anestetic [448]
3 years ago
7

the pressure of a sample of helium in a 0.150 L container is 1520 torr. if the helium is compressed to the volume of 0.012 L wit

hout changing the temperature what would be the pressure of the gas
Chemistry
1 answer:
Firlakuza [10]3 years ago
5 0

Answer:

19000 torr

Explanation:

From the question given above, the following data were obtained:

Initial volume (V₁) = 0.150 L

Initial pressure (P₁) = 1520 torr

Final volume (V₂) = 0.012 L

Temperature = constant

Final pressure (P₂) =?

The final pressure of the gas can be obtained by using the Boyle's law equation as illustrated below:

P₁V₁ = P₂V₂

1520 × 0.150 = P₂ × 0.012

228 = P₂ × 0.012

Divide both side by 0.012

P₂ = 228 / 0.012

P₂ = 19000 torr

Thus, the final pressure of the gas is 19000 torr

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Na2CO3 + 2HCl ---------> 2NaCl + CO2 + H2O How many moles of NaCl are produced from the reaction of 1.67 x 1022 molecules of
dexar [7]

Answer:

0.0554 moles of NaCl are produced from the reaction of 1.67*10²² molecules of Na₂CO₃ with excess HCl.

Explanation:

The balanced reaction is:

Na₂CO₃ + 2 HCl → 2 NaCl + CO₂ + H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:

  • Na₂CO₃: 1 mole
  • HCl: 2 moles
  • NaCl: 2 moles
  • CO₂: 1 mole
  • H₂O: 1 mole

On the other hand, Avogadro's Number is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023*10²³ particles per mole. Avogadro's number applies to any substance.

In this case, you can apply the following rule of three: if 6.023*10²³ molecules of Na₂CO₃ are contained in 1 mole, 1.67*10²² molecules will be contained in how many moles?

amount of moles=\frac{1.67*10^{22}molecules*1mole }{6.023*10^{23}molecules}

amount of moles= 0.0277 moles

In this case, you can apply the following rule of three: if by stoichiometry 1 mole of Na₂CO₃ produces 2 moles of NaCl, 0.0277 moles of Na₂CO₃ will produce how many moles of NaCl?

amount of moles of NaCl=\frac{0.0277 moles of Na_{2} CO_{3}*2 moles of NaCl }{1 mole of Na_{2} CO_{3}}

amount of moles of NaCl= 0.0554 moles

<u><em>0.0554 moles of NaCl are produced from the reaction of 1.67*10²² molecules of Na₂CO₃ with excess HCl.</em></u>

8 0
3 years ago
Please answer fast!
Over [174]

Explanation:

they are located in the neucleus

4 0
4 years ago
What is the molarity of NaOH, if 15g of NaOH is mixed with 600mL?
inn [45]
M(NaOH)=15 g

v=600 ml=0.6 l

n(NaOH)=m(NaOH)/M(NaOH)

C=n(NaOH)/v=m(NaOH)/[M(NaOH)v]

C=15g/[40g/mol*0.6 l]=0.625 mol/l

0.625M



[H⁺]=7.5*10⁻²
pOH=14-pH=14+lg[H⁺]
pOH=14+lg(7.5*10⁻²)=14-1.125=12.875
5 0
4 years ago
Con someone please help me balance this equation
Paladinen [302]

Answer:

3, 2, 1, 6

Explanation:

- Make a list of each element and the amount it contains.

- Multiply them out to get them equivalent.

- Hope that helped! Please let me know if you need further explanation.

8 0
4 years ago
Read 2 more answers
What is the mass of 0.2 moles of ethanol​
Verdich [7]

Answer:

<u>Answer</u><u> </u><u>is</u><u> </u><u>9</u><u>.</u><u>2</u><u> </u><u>grams</u>

Explanation:

Molar mass of ethanol

{ \bf{CH _{3}CH_{2}OH}} = (12 \times 2) + (6 \times 1) + (16) \\  = 46 \: g

for moles:

{ \sf{1 \: mole \: of \: ethanol \: weighs \: 46 \: g}} \\ { \sf{0.2 \: moles \: weigh \: (0.2 \times 46) \: g}} \\  = 9.2 \: g

4 0
3 years ago
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