Answer:
0.0554 moles of NaCl are produced from the reaction of 1.67*10²² molecules of Na₂CO₃ with excess HCl.
Explanation:
The balanced reaction is:
Na₂CO₃ + 2 HCl → 2 NaCl + CO₂ + H₂O
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:
- Na₂CO₃: 1 mole
- HCl: 2 moles
- NaCl: 2 moles
- CO₂: 1 mole
- H₂O: 1 mole
On the other hand, Avogadro's Number is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023*10²³ particles per mole. Avogadro's number applies to any substance.
In this case, you can apply the following rule of three: if 6.023*10²³ molecules of Na₂CO₃ are contained in 1 mole, 1.67*10²² molecules will be contained in how many moles?

amount of moles= 0.0277 moles
In this case, you can apply the following rule of three: if by stoichiometry 1 mole of Na₂CO₃ produces 2 moles of NaCl, 0.0277 moles of Na₂CO₃ will produce how many moles of NaCl?

amount of moles of NaCl= 0.0554 moles
<u><em>0.0554 moles of NaCl are produced from the reaction of 1.67*10²² molecules of Na₂CO₃ with excess HCl.</em></u>
Explanation:
they are located in the neucleus
M(NaOH)=15 g
v=600 ml=0.6 l
n(NaOH)=m(NaOH)/M(NaOH)
C=n(NaOH)/v=m(NaOH)/[M(NaOH)v]
C=15g/[40g/mol*0.6 l]=0.625 mol/l
0.625M
[H⁺]=7.5*10⁻²
pOH=14-pH=14+lg[H⁺]
pOH=14+lg(7.5*10⁻²)=14-1.125=12.875
Answer:
3, 2, 1, 6
Explanation:
- Make a list of each element and the amount it contains.
- Multiply them out to get them equivalent.
- Hope that helped! Please let me know if you need further explanation.
Answer:
<u>Answer</u><u> </u><u>is</u><u> </u><u>9</u><u>.</u><u>2</u><u> </u><u>grams</u>
Explanation:
Molar mass of ethanol

for moles:
