Answer:
-2.80 × 10³ kJ/mol
Explanation:
According to the law of conservation of energy, the sum of the heat absorbed by the bomb calorimeter (Qcal) and the heat released by the combustion of the glucose (Qcomb) is zero.
Qcal + Qcomb = 0
Qcomb = - Qcal [1]
We can calculate the heat absorbed by the bomb calorimeter using the following expression.
Qcal = C × ΔT = 4.30 kJ/°C × (29.51°C - 22.71°C) = 29.2 kJ
where,
C: heat capacity of the calorimeter
ΔT: change in the temperature
From [1],
Qcomb = - Qcal = -29.2 kJ
The internal energy change (ΔU), for the combustion of 1.877 g of glucose (MW 180.16 g/mol) is:
ΔU = -29.2 kJ/1.877 g × 180.16 g/mol = -2.80 × 10³ kJ/mol
Answer:
OUTCOME VARIABLE: Attraction to negatively charged balloon
Explanation:
In an experiment, two major variables must be included viz: the independent variable and the dependent variable. The independent variable also referred to as the test variable is the variable that is being changed in the experiment while the dependent or outcome variable is the variable that responds to the changes made to the independent variable. The outcome variable is the variable that is measured in an experiment.
In this experiment involving Marianne wanting to know which objects will be attracted to a negatively charged balloon. The type of objects are the independent variable while the ATTRACTION is the outcome or dependent variable as it is dependent on the type of object used.
Answer:
its compound option c compound comprises of two or more atoms
Answer:

Explanation:
<u>1. Calculate the mass of C in 1.24 g of CO₂</u>

<u>2. Calculate the mass of H in 0.255g of H₂O</u>

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<u>3. Calculate the mass of O by difference</u>

<u>4. Convert every mass to number of moles:</u>
- C: 0.3384g / (12.011g/mol) = 0.02817 mol
- H: 0.02854g / (1.008g/mol) = 0.02831 mol
- O: 0.15206g / (15.999g/mol) = 0.009504 mol
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<u>5. Divide every number of moles by the least number of moles (0.009504):</u>
- C: 0.02817/0.009504 = 2.96 ≈ 3
- H: 0.02831 / 0.009504 ≈ 3
- O: 0.009504 / 0.009504 = 1
<u>6. Those numbers are the respective subscripts in the empirical formula:</u>

Nuclear fission because an atom is splitting....