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marta [7]
3 years ago
10

Con someone please help me balance this equation

Chemistry
2 answers:
Paladinen [302]3 years ago
8 0

Answer:

3, 2, 1, 6

Explanation:

- Make a list of each element and the amount it contains.

- Multiply them out to get them equivalent.

- Hope that helped! Please let me know if you need further explanation.

kozerog [31]3 years ago
7 0
3,2,1,6 is the answers
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Radon-222 is a radioactive gas with a half-life of 3.82 days. How long would it take for fifteen-sixteenths of a sample of radon
Fittoniya [83]
Use the formula in terms of half life from the normal exponential functions 
<span>
N(t) = N(0) (1/2) ^ (t/thalf) </span>
<span>
N(0) is the original quantity </span>
<span>
N(t) = quantity remaining at time t </span>
<span>
t is the time </span>
<span>

thalf is half life </span>
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1/16 = (1/2)^(t/3.82) </span>
<span>
16 = 2^(t/3.82) </span>
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4 = t/3.82 </span>
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I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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3 years ago
How many mL of 0.506 M HClare needed to dissolve 9.85 g of BaCO3?
Blababa [14]

Answer:

197mL of 0,506M HCl

Explanation:

The reaction of HCl + BaCO₃ is:

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9,85 g of BaCO₃ × \frac{1mol}{197,34 g} = <em>0,0499 moles of BaCO₃</em>

As 1 mol of BaCO₃ reacts with two moles of HCl, for a complete reaction of BaCO₃ to dissolve this compound in water you need:

0,0499 moles of BaCO₃ × \frac{2molHCl}{1molBaCO_{3}} =<em> 0,0998 moles of HCl</em>

If you have a 0,506M HCl, you need to add:

0,0998 moles of HCl× \frac{1L}{0,506moles} = 0,197 L ≡ 197mL

I hope it helps!

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