Answer:
The ration of the molar solubility is 165068.49.
Explanation:
The solubility reaction of the magnesium hydroxide in the pure water is as follows.

![[Mg^{2+}][OH^{-}]](https://tex.z-dn.net/?f=%5BMg%5E%7B2%2B%7D%5D%5BOH%5E%7B-%7D%5D)
Initial 0 0
Equili +S +2S
Final S 2S
![K_{sp}=[Mg^{2+}][OH^{-}]](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BMg%5E%7B2%2B%7D%5D%5BOH%5E%7B-%7D%5D)


Solubility of
in 0.180 M NaOH is a follows.

![[Mg^{2+}][OH^{-}]](https://tex.z-dn.net/?f=%5BMg%5E%7B2%2B%7D%5D%5BOH%5E%7B-%7D%5D)
Initial 0 0
Equili +S +2S
Final S 2S+0.180M
![K_{sp}=[Mg^{2+}][OH^{-}]](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BMg%5E%7B2%2B%7D%5D%5BOH%5E%7B-%7D%5D)



Therefore, The ration of the molar solubility is 165068.49.
Freidal craft reaction is the attack of a carbon or carbon chain on aromatic ring with the help of anhydrous AlCl3 to produce alkylated benzene ring.
Only ketone not be able to undergo friedal craft reaction as, it is not aromatic compound whereas all the given reactants are aromatic and gives friedal craft reaction.
This question comes with four answer choices:
<span>A. H2O + H2O ⇄ 2H2 + O2
B. H2O + H2O⇄ H2O2 + H2
C. H2O + H2O ⇄ 4H+ + 2O2-
D. H2O + H2O ⇄ H3O+ + OH-
Answer: option </span><span>D. H2O + H2O ⇄ H3O+ + OH-
(the +sign next to H3O is a superscript, as well as the - sing next to OH)
Explanation:
The self-ionization of water, or autodissociation, produces the two ions H3O(+) and OH(-). The presence of ions is what explain the electrical conductivity of pure water.
</span><span>In this, one molecule of H2O loses a proton (H+) (deprotonates) to become a hydroxide ion, OH−. Then, he <span>hydrogen ion, H+</span>, immediately protonates another water molecule to form hydronium, H3O+.
</span>
A) polyester, hope it was quick enough