Answer: y = x
<u>Step-by-step explanation:</u>
First, find the point where 5x - 2y + 3 and 4x - 3y + 1 intersect using the Elimination Method.
5x - 2y + 3 = 0 → 3(5x - 2y + 3 = 0) → 15x - 6y + 9 = 0
4x - 3y + 1 = 0 → -2(4x - 3y + 1 = 0) → <u> -8x + 6y - 2</u> =<u> 0 </u>
7x + 7 = 0
7x = -7
x = -1
5x - 2y + 3 = 0
5(-1) - 2y + 3 = 0
-5 - 2y + 3 = 0
-2y - 2 = 0
-2y = 2
y = -1
(-1, -1)
Next, find the point where x = y and x = 3y + 4 intersect using the Substitution Method.
x = y
x = 3y + 4 → y = 3y + 4
-2y = 4
y = -2
x = y
x = -2
(-2, -2)
Now, find the line that passes through (-1, -1) and (-2, -2) using the Point-Slope formula. (x₁, y₁) = (-1, -1) and m = 1
y - y₁ = m(x - x₁)
y + 1 = 1(x + 1)
y = x
Answer:1 and 3 answer a
Step-by-step explanation:
6.974 rounded to the nearest tenth is 6.97 i think
Answer:
a) The domain of f(x) is
.
b)
The inverse function is:
![y = \ln{(e^{x} + 3)}The domain is all the real values of x.Step-by-step explanation:(a) Find the domain off f(x) = ln(e^x − 3)The domain of f(x) = ln(g(x)) is g(x) > 0. That means that the ln function only exists for positive values.So, here we have[tex]g(x) = e^{x} - 3](https://tex.z-dn.net/?f=y%20%3D%20%5Cln%7B%28e%5E%7Bx%7D%20%2B%203%29%7D%3C%2Fp%3E%3Cp%3EThe%20domain%20is%20all%20the%20real%20values%20of%20x.%3C%2Fp%3E%3Cp%3E%3Cstrong%3EStep-by-step%20explanation%3A%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3E%3Cstrong%3E%28a%29%20Find%20the%20domain%20off%20f%28x%29%20%3D%20ln%28e%5Ex%20%E2%88%92%203%29%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3EThe%20domain%20of%20f%28x%29%20%3D%20ln%28g%28x%29%29%20is%20g%28x%29%20%3E%200.%20That%20means%20that%20the%20ln%20function%20only%20exists%20for%20positive%20values.%3C%2Fp%3E%3Cp%3ESo%2C%20here%20we%20have%3C%2Fp%3E%3Cp%3E%5Btex%5Dg%28x%29%20%3D%20e%5E%7Bx%7D%20-%203)
So we need
![e^{x} - 3 > 0](https://tex.z-dn.net/?f=e%5E%7Bx%7D%20-%203%20%3E%200)
![e^{x} > 3](https://tex.z-dn.net/?f=e%5E%7Bx%7D%20%3E%203)
Applying ln to both sides
![\ln{e^{x}} > \ln{3}](https://tex.z-dn.net/?f=%5Cln%7Be%5E%7Bx%7D%7D%20%3E%20%5Cln%7B3%7D)
![x > 1.1](https://tex.z-dn.net/?f=x%20%3E%201.1)
So the domain of f(x) is
.
(b) Find F −1 and its domain.
is the inverse function of f.
How do we find the inverse function?
To find the inverse equation, we change y with x to form the new equation, and then we isolate y in the new equation. So:
Original equation:
f(x) = y = \ln{e^{x} - 3}
New equation
![x = \ln{e^{y} - 3}](https://tex.z-dn.net/?f=x%20%3D%20%5Cln%7Be%5E%7By%7D%20-%203%7D)
Here, we apply the exponential to both sides:
![e^{x} = e^{\ln{e^{y} - 3}}](https://tex.z-dn.net/?f=e%5E%7Bx%7D%20%3D%20e%5E%7B%5Cln%7Be%5E%7By%7D%20-%203%7D%7D)
![e^{y} - 3 = e^{x}](https://tex.z-dn.net/?f=e%5E%7By%7D%20-%203%20%3D%20e%5E%7Bx%7D)
![e^{y} = e^{x} + 3](https://tex.z-dn.net/?f=e%5E%7By%7D%20%3D%20e%5E%7Bx%7D%20%2B%203)
Applying ln to both sides
![\ln{e^{y}} = \ln{e^{x} + 3}](https://tex.z-dn.net/?f=%5Cln%7Be%5E%7By%7D%7D%20%3D%20%5Cln%7Be%5E%7Bx%7D%20%2B%203%7D)
The inverse function is:
![y = \ln{e^{x} + 3}](https://tex.z-dn.net/?f=y%20%3D%20%5Cln%7Be%5E%7Bx%7D%20%2B%203%7D)
The domain is
![e^{x} + 3 > 0](https://tex.z-dn.net/?f=e%5E%7Bx%7D%20%2B%203%20%3E%200)
![e^{x} > -3](https://tex.z-dn.net/?f=e%5E%7Bx%7D%20%3E%20-3)
is always a positive number, so it is always going to be larger than -3 no matter the value of x. So the domain are all the real values.