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lidiya [134]
3 years ago
7

+ 10x \leqslant 21" alt="(x +3)^{2} + 10x \leqslant 21" align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
erik [133]3 years ago
5 0

Step-by-step explanation:

{(x + 3)}^{2}  + 10x\leqslant 10 \\  {x}^{2}  + 6x + 9 + 10x \leqslant 10 \\  {x}^{2}  + 16x + 9 \leqslant 10 \\  {x}^{2}  + 6x + 9 \leqslant 0 \\ the \: value \: of \: x \: that \: makes \: it \: exist \\ x =  - 3

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