<img src="https://tex.z-dn.net/?f=%28x%20%2B3%29%5E%7B2%7D%20%20%2B%2010x%20%5Cleqslant%2021" id="TexFormula1" title="(x +3)^{2}

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lidiya [134]

3 years ago

+ 10x \leqslant 21" alt="(x +3)^{2} + 10x \leqslant 21" align="absmiddle" class="latex-formula">

Mathematics

1 answer:

erik [133]3 years ago

5 0

Step-by-step explanation:

${(x + 3)}^{2} + 10x\leqslant 10 \\ {x}^{2} + 6x + 9 + 10x \leqslant 10 \\ {x}^{2} + 16x + 9 \leqslant 10 \\ {x}^{2} + 6x + 9 \leqslant 0 \\ the \: value \: of \: x \: that \: makes \: it \: exist \\ x = - 3$

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