Question

Please help me I will give branliest! Find the indicated trig ratio and write your answer as a simplified fraction. Image attached

Answer 1

Step-by-step explanation:

secx=1/cosx

=1/(root of 11/6)

=6/root 11

=6root 11/11

Answer 2

Answer:

sec θ = $\frac{6\sqrt{11} }{11}$

Step-by-step explanation:

Using the identity

sec x = $\frac{1}{cosx}$

cosθ = $\frac{adjacent}{hypotenuse}$ = $\frac{\sqrt{11} }{6}$ , then

secθ = $\frac{6}{\sqrt{11} }$ × $\frac{\sqrt{11} }{\sqrt{11} }$ = $\frac{6\sqrt{11} }{11}$