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3 years ago

The cost per month is a good way to compare different modes of transportation.

Mathematics

2 answers:

Nat2105 [25]3 years ago

5 0

The answer is A. True hope this right

kenny6666 [7]3 years ago

5 0

Answer:

The correct option is A. TRUE

Step-by-step explanation:

The cost per month tells us about all the expenses and the fess paid by us for that specific month.

Also, it tells us about the transportation expense for that month

Now, for example if one travels by bus for the first month then by using the cost per month one can find the transportation cost for that month and for the first month he travels by metro then by using the cost per month one can find the transportation cost for that month.

So, he is having transportation cost for both the months. So he can easily compare the different modes of transportation by using the cost per month and can easily identify which mode is cheaper and economical to travel.

So, The given statement is TRUE

Therefore, The correct option is A. TRUE

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Please help me find the answer and explain the process to find the answer of the problem appreciate it :)

Natalka [10]

Answer:

Total distance traveled is 67.653 miles

Step-by-step explanation:

Side a = 14 (miles traveled South)

Side b = 25 (miles traveled East)

side c = $a^{2} + b^{2}$

196 + 625 = $c^{2}$

821 = $c^{2}$

$\sqrt{821} = \sqrt{c^{2} }$

c = 28.653 (rounded to the nearest 1000th)

Now add the three sides to get the total distance:

14 + 25 + 28.653 = 67.653

5 0

3 years ago

-3(x - 2) - 2x + 4x^2

Fantom [35]

Answer:

-6x+6+4x^2

Step-by-step explanation:

Distribute the -3

-3(x-2)= -3x+6

Combine like terms

-3x+6-2x+4x^2

-6x+6+4x^2

8 0

3 years ago

Can someone please help me?

kvasek [131]

now, let's recall the rational root test, check your textbook on it.

so p = 18 and q = 1

so all possible roots will come from the factors of ±p/q

now, to make it a bit short, the factors are loosely, ±3, ±2, ±9, ±1, ±6.

recall that, a root will give us a remainder of 0.

let us use +3.

$\bf x^4-7x^3+13x^2+3x-18 \\\\[-0.35em] ~\dotfill\\\\ \begin{array}{r|rrrrr} 3&1&-7&13&3&18\\ &&3&-12&3&18\\ \cline{1-6} &1&-4&1&6&0 \end{array}\qquad \implies (x-3)(x^3-4x^2+x+6)$

well, that one worked... now, using the rational root test, our p = 6, q = 1.

so the factors from ±p/q are ±3, ±2, ±1

let's use 3 again

$\bf \begin{array}{r|rrrrr} 3&1&4&1&6\\ &&3&-3&-6\\ \cline{1-5} &1&-1&-2&0 \end{array}\qquad \implies (x-3)(x-3)(x^2-x-2)$

and of course, we can factor x²-x-2 to (x-2)(x+1).

(x-3)(x-3)(x-2)(x+1).

7 0

3 years ago

You are trying to forecast coffee sales for the holiday season. You sold 1,500 cups of coffee during the holidays last year, but

Airida [17]

Hello there!

You expect to sell 100% - 20% = 80% of many coffee sales.

0.80 * 1500 = 1200

Your answer is 1200 cups of coffee.

Hope I helped!

Let me know if you need anything else!

~ Zoe

5 0

3 years ago

Ive been on this question for a while as homework and im stuck help?

iogann1982 [59]

Answer:

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3 years ago