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3 years ago

The cost per month is a good way to compare different modes of transportation.

Mathematics

2 answers:

Nat2105 [25]3 years ago

5 0

The answer is A. True hope this right

kenny6666 [7]3 years ago

5 0

Answer:

The correct option is A. TRUE

Step-by-step explanation:

The cost per month tells us about all the expenses and the fess paid by us for that specific month.

Also, it tells us about the transportation expense for that month

Now, for example if one travels by bus for the first month then by using the cost per month one can find the transportation cost for that month and for the first month he travels by metro then by using the cost per month one can find the transportation cost for that month.

So, he is having transportation cost for both the months. So he can easily compare the different modes of transportation by using the cost per month and can easily identify which mode is cheaper and economical to travel.

So, The given statement is TRUE

Therefore, The correct option is A. TRUE

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lyudmila [28]

${\large{\textsf{\textbf{\underline{\underline{Given :}}}}}}$

★ ∆ ABC is similar to ∆DEF

★ Area of triangle ABC = 64cm²

★ Area of triangle DEF = 121cm²

★ Side EF = 15.4 cm

${\large{\textsf{\textbf{\underline{\underline{To \: Find :}}}}}}$

★ Side BC

${\large{\textsf{\textbf{\underline{\underline{Solution :}}}}}}$

Since, ∆ ABC is similar to ∆DEF

[ Whenever two traingles are similar, the ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides. ]

$\therefore \tt \boxed{ \tt \dfrac{area( \triangle \: ABC )}{area( \triangle \: DEF)} = { \bigg(\frac{BC}{EF} \bigg)}^{2} }$

❍ Putting the values, [Given by the question]

• Area of triangle ABC = 64cm²

• Area of triangle DEF = 121cm²

• Side EF = 15.4 cm

$\implies \tt \dfrac{64 \: {cm}^{2} }{12 \: {cm}^{2} } = { \bigg( \dfrac{BC}{15.4 \: cm} \bigg) }^{2}$

❍ By solving we get,

$\implies \tt \sqrt{\dfrac{{64 \: cm}^{2} }{ 121 \: {cm}^{2} }} = \bigg( \dfrac{BC}{15.4 \: cm} \bigg)$

$\implies \tt \sqrt{\dfrac{{(8 \: cm)}^{2} }{ {(11 \: cm)}^{2} }} = \bigg( \dfrac{BC}{15.4 \: cm} \bigg)$

$\implies \tt \dfrac{8 \: cm}{11 \: cm} = \dfrac{BC}{15.4 \: cm}$

$\implies \tt \dfrac{8 \: cm \times 15.4 \: cm}{11 \: cm} = BC$

$\implies \tt \dfrac{123.2 }{11 } cm = BC$

$\implies \tt \purple{ 11.2 \: cm} = BC$

Hence, BC = 11.2 cm.

${\large{\textsf{\textbf{\underline{\underline{Note :}}}}}}$

★ Figure in attachment.

$\rule{280pt}{2pt}$

4 0

2 years ago

Find the quation of the quadratic function with roots 0 and 4 and a vertex at (2,-2)

Nookie1986 [14]

Answer:

y = (1/2)x² -2x

Step-by-step explanation:

recall that the general equation of a quadratic function is:

y = Ax² + Bx + C

given that 0 and 4 are roots, that means when x = 0 and x = 4, then y = 0

From this we can get 2 points on the curve, namely, (0,0) and (4,0)

substituting these points one at a time into the equation above,

for the first point (0,0),

0 = A (0)² + b(0) + C

C = 0

hence the equation becomes: y = Ax² + Bx

for the 2nd known point (4,0)

0 = A(4)² + B(4)

0 = 16A + 4B (divide both sides by 4)

0 = 4A + B

B = -4A ------------(eq 1)

we are given a 3rd point, vertex at (2,-2)

for (2,-2)

-2 = A(2²) + B(2)

-2 = 4A + 2B (divide both sides by 2)

-1 = 2A + B (subtract 2A from both sides)

B = -1 -2A --------(eq 2)

solving the system of equations using the method of your choice in eq1 and eq 2 gives:

A = 1/2 and B = -2

hence the equation is

y = (1/2)x² -2x

7 0

3 years ago

What do they say again oh yeah life is hard don't you think so too ?

Shkiper50 [21]

Not really because my life is gooing good

4 0

3 years ago

Read 2 more answers

Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s). Rewrite the fol

never [62]

Vertex Form: y = a(x - h)^2 + k, with (h,k) as the vertex.

To convert it into vertex form, we are going to be completing the square. Firstly, subtract 56 on both sides: $y-56=2x^2-32x$

Next, factor out the GCF, or greatest common factor, of the right side. To find the GCF, list the factors of both terms and the greatest one they share is their GCF. In this case, the GCF is 2: $y-56=2(x^2-16x)$

Next, we want to make what's inside the parentheses a perfect square. To find the constant of the perfect square, divide the x term by 2 and square the quotient. In this case:

-16 ÷ 2 = -8, (-8)² = 64

So you're gonna have to add 64 to the inside of the parentheses. To cancel this out, you will need to add to the other side the product of 64 and 2 (since 64 is inside the parentheses), which is 128: $y+72=2(x^2-16x+64)$