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Zielflug [23.3K]
3 years ago
15

A random number from 1 to 5 is selected

Mathematics
1 answer:
shutvik [7]3 years ago
7 0

Answer:

Relative frequency of selecting a 2 = 8/50 = 0.16

Relative frequency of selecting a 3 = 14/50 = 0.28

Step-by-step explanation:

When we have a given experiment with given outcomes (such that each time that we perform the experiment, one outcome happens) the relative frequency of a given outcome is the quotient between the number of times that that outcome happened, and the total number of times that the experiment was performed.

Here the experiment is selecting a random number between 1 and 5, and it is performed 50 times.

Out of these 50 times, the outcome "2" appears 8 times.

Then the relative frequency of selecting the number 2 is:

f(2) = 8/50 = 0.16

And of these 50 experiments, the outcome "3" appears 14 times.

Then the relative frequency of selecting the number 3 is:

f(3) = 14/50  = 0.28

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In the figure, TP and TS are opposite rays. TQ bisects < RTP.
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Answer:

search-icon-image

Class 9

>>Maths

>>Quadrilaterals

>>Quadrilaterals and Their Various Types

>>In Fig. 6.43, if PQ PS, PQ∥ SR, SQR = 2

Question

Bookmark

In Fig. 6.43, if PQ⊥PS,PQ∥SR,∠SQR=28

0

and ∠QRT=65

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, then find the values of x and y.

463685

expand

Medium

Solution

verified

Verified by Toppr

Given, PQ⊥PS,PQ∥SR,∠SQR=28

∘

,∠QRT=65

∘

According to the question,

x+∠SQR=∠QRT (Alternate angles as QR is transversal.)

⇒x+28

∘

=65

∘

⇒x=37

∘

Also ∠QSR=x

⇒∠QSR=37

∘

Also ∠QRS+∠QRT=180

∘

(Linear pair)

⇒∠QRS+65

∘

=180

∘

⇒∠QRS=115

∘

Now, ∠P+∠Q+∠R+∠S=360

∘

(Sum of the angles in a quadrilateral.)

⇒90

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+65

∘

+115

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+∠S=360

∘

⇒270

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+y+∠QSR=360

∘

⇒270

∘

+y+37

∘

=360

∘

⇒307

∘

+y=360

∘

⇒y=53

∘

Step-by-step explanation:

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