Answer: The event air molecules that are surrounding the metal will speed up, and the molecules in the metal will slow down would most likely take place over the next few minutes.
Explanation:
A process in which heat is evolved is called an exothermic process.
When hot metal plate at is placed in air at room temperature then heat is given off by the metal plate due to which there will occur a decrease in kinetic energy of its molecules.
As a result, molecules in the metal will slow down.
Whereas heat is absorbed by the air molecules from the metal due to which kinetic energy of air molecules will increase.
Thus, we can conclude that the event air molecules that are surrounding the metal will speed up, and the molecules in the metal will slow down would most likely take place over the next few minutes.
Answer:
2060.775 J
Explanation:
From the question given above, we obtained the following data:
Specific heat capacity (C) = 0.129 J/g°C
Mass (m) = 355 g
Initial temperature (Tᵢ) = 95 °C
Final temperature (Tբ) = 140 °C
Heat (Q) tranfered =?
We can calculate the amount of heat transferred by using the following formula:
Q = mC(Tբ – Tᵢ)
Q = 355 × 0.129 (140 – 95)
Q = 45.795 × 45
Q = 2060.775 J
Thus, 2060.775 J of energy was transferred.
Answer:
18
At STP, 22.4 liters of a gas forms one mole that is 6.023×10
23
molecules.
Volume of CO
2
in 1 litre of air =
100
0.03
×1 L
∴ No. of molecules of CO
2
=
22.4
6.023×10
23
×
100
0.03
=8.066×10
18
Explanation:
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Answer:
1.3 atm
Explanation:
Apply the ideal gas law: PV = nRT
Since we need to find the pressure, solve for pressure:
P = nRT / V
Plug in our given values of n = 4.6 moles, R = 0.08206 (ideal gas law constant using atm), T = 325 K, and V = 96.8 L:
P = 4.6(0.08206)(325) / 96.8 = 1.267 atm -> 1.3 atm (two significant figures)