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AveGali [126]
2 years ago
9

What is the surface area of the right rectangular prism?

Mathematics
2 answers:
garri49 [273]2 years ago
6 0

Answer:

Hello! answer:

Step-by-step explanation:

6 × 12 = 72

6 × 12 = 72

3 × 12 = 36

3 × 12 = 36

3 × 6 = 18

3 × 6 = 18

72 + 72 + 36 + 36 + 18 + 18 = 252 therefore the surface area would be 252 hope that helps!

Vladimir [108]2 years ago
5 0

Answer:

252 in²

Step-by-step explanation:

You have to calculate the area of each surface and sum all they after:

Top area: 6 × 12 = 72 in

Front area: 3 × 12 = 36 in

Side area: 6 × 3 = 18 in

You have 2 rectangles with the same measure of the top, of the side and the front, so multiply each area per 2:

72 × 2 = 144

36 × 2 = 72

18 × 2 = 36

Now you sum all the areas:

144 + 72 + 36 = 252 in²

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<u>Answer: x-axis</u>

<u><em>Explanation</em></u>:

  • x-axis: it is the horizonzontal axis
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1 year ago
The question is in the picture. Plz helppp it is due tonight
Mkey [24]

Answer:

Step-by-step explanation:

We're given one equation, we have to find the other equation and solve each for 200, and whichever has the lower x is the winner

for Jayden we are given

(0, 48), (1, 56), (2, 64), (3, 72), (4, 80)

This looks to be a line. The y values are each separated by a common difference

We can use two points to describe the line

m = \frac{y_2-y_1}{x_2-x_1} = \frac{80-48}{4-0} = \frac{32}{4} = 8\\  K = 8m + b\\48 = 8(0) + b\\b = 48\\so\\K = 8m + 48

Now we can set both K = 8m + 48 and K = m^2 + 10 equal to 200

200 = 8m + 48\\152 = 8m \\m = \frac{152}{8} = 19

200 = m^2 + 10\\m^2 = 190\\m = \sqrt{190} = 13.784

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7 0
3 years ago
The scores for a certain test of intelligence are normally distributed with mean 85 and standard deviation 11. Find the 90th per
jonny [76]

Answer:

99.1 is the 90th percentile of these scores.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 85

Standard Deviation, σ = 11

We are given that the distribution of score is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

We have to find the value of x such that the probability is 0.90

P( X < x) = P( z < \displaystyle\frac{x - 85}{11})=0.90  

Calculation the value from standard normal z table, we have,  

P(z \leq 1.282) = 0.90

Putting values, we get,

\displaystyle\frac{x - 85}{11} = 1.282\\\\x = 99.1

Thus, 99.1 is the 90th percentile of these scores.

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3 years ago
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Westkost [7]
Whole numbers start from 0 so i am guessing that you can find the decimal for 5/6=0.833 and then multiply .
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