Answer:
A
Step-by-step explanation:
x=
−b±√b2−4ac
2a
x=
−(2)±√(2)2−4(2)(15)
2(2)
x=
−2±√−116
4
and there is really no solution
Answer: Non of the option.
Step-by-step explanation:
The given equation is
4x^3 - 6x^2 + 15x + 2 = 0
Let's test 1, if it's one of the root. I.e
If x = 1
4 - 6 + 15 + 2 = 15
Positive 1 is not a root to the equation
If x = - 1
-4 - 6 - 15 + 2 = - 23
Negative 1 is not a root
If x = 2
4x8 - 6×4 + 15×4 + 2
32 - 24 + 30 + 2 = 40
Positive 2 is not a root
If x = - 2
4×(-8) - 6×4 - 15×2 + 2
-32 - 24 - 30 + 2 = -84
Negative 2 is not a root
If x = 3
4×27 - 6×9 + 15×3 + 2
108 - 54 + 45 + 2 = 101
Since non of them tend to zero, non of the option is a root of the equation
I believe it would be 4 lil man
Answer:
x= -2 and x = 6
Step-by-step explanation:
The solutions are where the two graphs intersect
x=6, y= 10 is one point
x=-2 and y = -6 is the other point
