Solve the following equation 3x^2-2x= 5

PLEASE HELP ME ASAP!!!<br> I WILL MARK BRAINLIEST!!

frutty [35]

Answer: {y/y>-4}

Step-by-step explanation:

7 0

4 years ago

A different car can travel 30.5 miles for every gallon of gas used

ohaa [14]

Answer:

Step-by-step explanation:

Yes, this distance will be different depends on the car, exactly the car's motor, we could have the same gasoline litter but if we have a car with a small motor the gasoline would last longer.

For example:

A small car could travel more miles than a big car with a v6 motor, a small car could use 4 litter in an hour, in a truck could use 8 litter or more in an hour depends on the motor, assuming we traveled 24.2 miles per hour.

3 0

4 years ago

Read 2 more answers

What is the value of X in the figure?<br> Enter your answer in the box.<br> X =

hichkok12 [17]

Answer:

29 degrees

Step-by-step explanation:

x + 61 = 90

x = 90 - 61

x = 29

6 0

3 years ago

Read 2 more answers

A jet travels 2301 miles against the wind in 3 hours and 2811 miles with the wind in the same amount of time. What is the rate o

astraxan [27]

Answer:

The rate of the jet in still air is 852 miles per hour. The rate of the wind is 85 miles per hour.

Step-by-step explanation:

Let suppose that jet travels uniformly, that is, at constant speed, the expressions for its travels against the wind and with the wind are, respectively:

Against the wind

$v -u = \frac{\Delta x_{1}}{\Delta t_{1}}$

With the wind

$v +u = \frac{\Delta x_{2}}{\Delta t_{2}}$

Where:

$v$ - Speed of the jet in still air, measured in miles per hour.

$u$ - Speed of wind, measured in miles per hour.

$\Delta x_{1}$ , $\Delta x_{2}$ - Distances travelled by jet against the wind and with the wind, measured in miles.

$\Delta t_{1}$ , $\Delta t_{2}$ - Times against the wind and with the wind, measured in hours.

By adding both expressions:

$2\cdot v = \frac{\Delta x_{1}}{\Delta t_{1}}+\frac{\Delta x_{2}}{\Delta t_{2}}$

$v = \frac{1}{2}\cdot \left(\frac{\Delta x_{1}}{\Delta t_{1}} + \frac{\Delta x_{2}}{\Delta t_{2}} \right)$

Given that $\Delta x_{1} = 2301\,mi$ , $\Delta t_{1} = 3\,h$ , $\Delta x_{2} = 2811\,mi$ and $\Delta t_{2} = 3\,h$ , the speed of the jet is:

$v = \frac{1}{2}\cdot \left(\frac{2301\,mi}{3\,h}+\frac{2811\,mi}{3\,h} \right)$

$v = 852\,\frac{mi}{h}$

The rate of the jet in still air is 852 miles per hour.

Lastly, the rate of the wind is:

$u = \frac{\Delta x_{2}}{\Delta t_{2}}-v$

$u = \frac{2811\,mi}{3\,h}-852\,\frac{mi}{h}$

$u = 85\,\frac{mi}{h}$

The rate of the wind is 85 miles per hour.

5 0

3 years ago

find a positive angle less than one revolution around the unit circle that is co-terminal with the given angle -15pi/17

natta225 [31]

ANSWER
$=\frac{19}{17} \pi$

EXPLANATION

To find a positive angle that is coterminal with
$- \frac{15}{17} \pi$

We add multiples of 2π until we get a positive angle that is less than one revolution,

We add to obtain,

$- \frac{15}{17} \pi + 2\pi$

This simplifies to,

$= \frac{19}{17} \pi$

This is the first positive angle that is coterminal with
$- \frac{15}{17} \pi$

and is less than one revolution.

7 0

4 years ago

Solve the following equation 3x^2-2x= 5​

Solve the following equation 3x^2-2x= 5