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Ymorist [56]
3 years ago
12

Please I need help with one and 2 questions

Mathematics
1 answer:
kotykmax [81]3 years ago
7 0
I’ll help you what’s up
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Solve x2 - 8x = 20 by completing the square<br> {-22, 14}<br> {-14, 22}<br> {-10.2)<br> -(2.10)
alexgriva [62]
-10,2 is your answer when you simplify it
6 0
3 years ago
Solve:
mash [69]

Answer:

1. Infinitely Many Solutions

2. Zero Solutions

3. One Solution ( x = 6 )

Step-by-step explanation:

1.

12x + 8 = 2( 6x + 4 )

12x + 8 = 12x + 8

2.

2( 2x + 1 ) = 4x + 3

4x + 2 = 4x + 3

2 = 3

3.

4( x + 1 ) = 3x + 10

4x + 4 = 3x + 10

x + 4 = 10

x = 6

Hopefully this helps!

Brainliest please?

8 0
3 years ago
Pls help branliest if right
Bezzdna [24]

Answer:

sorry I donot know

I wish I could help

7 0
3 years ago
An apartment complex rents an average of 2.3 new units per week. If the number of apartment rented each week Poisson distributed
masya89 [10]

Answer:

P(X\leq 1) = 0.331

Step-by-step explanation:

Given

Poisson Distribution;

Average rent in a week = 2.3

Required

Determine the probability of renting no more than 1 apartment

A Poisson distribution is given as;

P(X = x) = \frac{y^xe^{-y}}{x!}

Where y represents λ (average)

y = 2.3

<em>Probability of renting no more than 1 apartment = Probability of renting no apartment + Probability of renting 1 apartment</em>

<em />

Using probability notations;

P(X\leq 1) = P(X=0) + P(X =1)

Solving for P(X = 0) [substitute 0 for x and 2.3 for y]

P(X = 0) = \frac{2.3^0 * e^{-2.3}}{0!}

P(X = 0) = \frac{1 * e^{-2.3}}{1}

P(X = 0) = e^{-2.3}

P(X = 0) = 0.10025884372

Solving for P(X = 1) [substitute 1 for x and 2.3 for y]

P(X = 1) = \frac{2.3^1 * e^{-2.3}}{1!}

P(X = 1) = \frac{2.3 * e^{-2.3}}{1}

P(X = 1) =2.3 * e^{-2.3}

P(X = 1) = 2.3 * 0.10025884372

P(X = 1) = 0.23059534055

P(X\leq 1) = P(X=0) + P(X =1)

P(X\leq 1) = 0.10025884372 + 0.23059534055

P(X\leq 1) = 0.33085418427

P(X\leq 1) = 0.331

Hence, the required probability is 0.331

6 0
3 years ago
A cylinder has a radius of 3 cm. Sand is poured into the cylinder to form a layer 2 cm deep. What is the volume of sand in the c
netineya [11]

Answer:

Volume=56.54cm³

Step-by-step explanation:

Solution,\\\\Radius(r)=3cm\\\\Height(h)=2cm\\\\Now,\\\\Volume=\pi r^{2} h\\\\Volume=\pi *(3cm)^{2} *2cm\\\\Volume=18\pi cm^{3} =56.54cm^{3}

3 0
2 years ago
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