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BaLLatris [955]
3 years ago
5

Which of these expressions is equivalent to log (20 27)

Mathematics
1 answer:
maria [59]3 years ago
8 0
If the problem is referring to the equivalent logarithmic equation log (20 *27).
We can easily find and solve its equivalent expression using one of the many identities available in logarithmic. 
We can have the expression:
log (20*27) = log 20 + log 27

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In triangle FGH shown below, what is the measure of ∠ F in degrees?
shutvik [7]

Answer:

33.5+127=160.5

180-160.5=19.5

Step-by-step explanation:

5 0
2 years ago
Write the following number in standard form: 3.471 x 10 to the power of negative 3
iogann1982 [59]

Answer:

=-3471 is the answer this may help you.

Step-by-step explanation:

=3.471×10^-3

=3.471×-1000

=-3471

8 0
3 years ago
Please Help!!
ryzh [129]

Answer:

3/2 times as far

Step-by-step explanation:

Mai's distance divided by Noah's distance will give you your answer.

6.75 divided by 4.5 is 1.5 which is 3/2 as a decimal.

4 0
3 years ago
i need help asap please dont type random anwsers, that will result in it being deleted. GIVING BRAINLIEST ONLY TO CORRECT, INCOR
Veseljchak [2.6K]

Answer:

The area of the rectangle <em>TOUR</em> is 80.00 unit².

Step-by-step explanation:

The area of a rectangle is computed using the formula:

Area\ of\ a\ Rectangle=length\times width

Since the dimensions of the rectangle are not provided we can compute the dimensions using the distance formula for two points.

The distance formula using the two point is:

distance=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}

Considering the rectangle <em>TOUR</em> the area formula will be:

Area of Rectangle <em>TOUR</em> = <em>TO × OU</em>

The co-ordinates of the four vertices of a triangle are:

T = (-8, 0), O = (4, 4), U = (6, -2) and R = (-6, -6)

Compute the distance between the vertices <em>T</em> and <em>O</em> as:

TO=\sqrt{(4-(-8))^{2}+(4-0)^{2}}\\=\sqrt{12^{2}+4^{2}} \\=\sqrt{160} \\=4\sqrt{10}

Compute the distance between the vertices <em>O </em>and <em>U</em> as:

OU=\sqrt{(6-4)^{2}+(-2-4)^{2}}\\=\sqrt{2^{2}+6^{2}} \\=\sqrt{40} \\=2\sqrt{10}

Compute the area of rectangle TOUR as follows:

Area\ of\ TOUR=TO\times OU\\=4\sqrt{10}\times 2\sqrt{10}\\=80\\\approx80.00 unit^{2}

Thus, the area of the rectangle <em>TOUR</em> is 80.00 unit².

6 0
3 years ago
Solve the equation for all values of x by completing the square.<br> x^2 + 4x = 32
Black_prince [1.1K]

Answer:

x^2+4x-32=0

(mid-term breaking---4 x 8=32)

x^2+8x-4x-32=0

x(x+8)-4(x+8)

x+8=0 or x-4=0

So x=+4 or x=-8

Step-by-step explanation:

7 0
3 years ago
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