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Firlakuza [10]
3 years ago
10

A circle is centered at the point (5, -4) and passes through the point (-3, 2).

Mathematics
2 answers:
mamaluj [8]3 years ago
7 0

Answer:

The answer to your question is    (x - 5)² + (x + 4) = 100

Step-by-step explanation:

Data

Center = (5, -4)

Point = (-3, 2)

Process

1.- Calculate the length of the radius

Formula

      d = \sqrt{(x2-x1)^{2} + (y2 - y1)^{2}}

Substitution

     d = \sqrt{(-3-5)^{2}+ (2 + 4)^{2}}

Simplification

     d = \sqrt{(-8)^{2}+ (6)^{2}}

     d= \sqrt{64 + 36}

     d = \sqrt{100}

     d = 10

2.- Get the equation of the line

     h = 5    k = -4    r = 10

     ( x - 5)² + (y + 4)² = 10²

Simplification and result

                               (x - 5)² + (x + 4) = 100

olya-2409 [2.1K]3 years ago
6 0

Answer:

The first space is 3,

The second space is -2

The third space is 100

Step-by-step explanation:

A circle with center (a, b) and has radius r has equation: (x-a)^{2} + (y-b)^{2} = r^{2}

Now, if the circle passes through (-3, 2) and it has center on (5, -4). That means the radius of the circle will be the distance between points (-3, 2) and (5, -4).

d = \sqrt{(x_{2} - x_{1} )^{2} + (y_{2} - y_{1} )^{2} }

where d = formula of distance between points (x_{2}, y_{2} ) \ and \ (x_{1}, y_{1} )

d = \sqrt{(-3-5)^{2} + (-4-2)^{2}  }\\ d = \sqrt{-8^{2} +  -6^{2} }\\ d = \sqrt{64+36}\\ d = \sqrt{100}\\ d = radius \ of \ circle = 10

Now, with r = 10, a = -3, b = 2

The equation of circle becomes:

(x-(-3))^{2} + (y-2)^{2}  = 10^{2} \\(x+3)^{2} + (y-2)^{2}  = 100 \\

The first space is 3,

The second space is -2

The third space is 100

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Sanjay sold 8kg of sugar at Rs 28 per kg and earned a profit of Rs 40 What was the cost price per kg
JulijaS [17]

Answer:

23

Step-by-step explanation:

8 kg * 28 per kg = Rs. 224

Profit = Rs. 40

CP = SP - Profit

224 - 40

184

184 / 8

23

4 0
2 years ago
HELP ILL GIVE BRAINLIEST PLSSS IM BEGGINg!!!
Tasya [4]

Answer:

37.5

Step-by-step explanation:

You would do 25 divided by two in order to find out what the distant in one inch is. 25 divided by two is 12.5. Then, you do 12.5 multiplied by 3.

7 0
3 years ago
Read 2 more answers
Can someone please help me find the domain, range, intercepts, and asymptotes pf this function?
marishachu [46]
1) given function

y = - 2 ^ ( -x + 2) + 1

2) domain: domain is the set of the x-values for which the function is defined.

The exponential function is defined for all the real numbers, so the domain of the given function is all the real numbers.

3) x-intercept => y = 0

=> y = - 2 ^ ( -x + 2) + 1 = 0 => 2^ ( -x + 2) = 1

=> - x + 2 = 0 => x = 2

The x-intercept is x = 0

4) y-intercept => x = 0

=> y = - 2 ^ ( -x + 2) + 1= - 2 ^ ( 0 + 2)  1 = - (2)^(2) + 1 =- 4 + 1 = - 3

=> The y-intercept is - 3

5) limit when x -> negative infinite

Lim f(x) when x -> ∞ = - ∞

6) limit when x -> infinite

Lim f(x) when x - > infinite = 1

=> asymptote = y = 1

7) range is the set of values of the fucntion: y

Given that the function is strictly decreasing from -∞ to ∞, the range is from - ∞ to less than 1

Range (-∞,1)


3 0
2 years ago
Please whats the answer to this question
Shkiper50 [21]
I believe it’s 800 cm^3
4 0
3 years ago
Read 2 more answers
WILL MARK BRAINLIEST!! The coordinates of the vertices of quadrilateral JKLM are J(-3,2), K(4,-1), L(2,-5) and M(-5,-2). Find th
irinina [24]
Answer:
JKLM is a parallelogram
Explanation:
The slope m of a line through two points (x1,y1) and (x2,y2)is given by the formula:
m=Δy/Δx=y2-y1/x2-x1
So the slopes of the sides of our quadrilateral are:
mJK=(−1)−24−(−3)=−37
mKL=(−5)−(−1)2−4=2
mLM=(−2)−(−5)−5−2=−37
mMJ=2−(−2)(−3)−(−5)=2
So JK is parallel to LM and KL is parallel to MJ
So JKLM is a parallelogram.
5 0
2 years ago
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