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Ronch [10]
3 years ago
8

Which of the following is NOT a typical tennis competition (connexus)

Mathematics
2 answers:
andrew11 [14]3 years ago
6 0

Answer:

as a tennis player, i know this

Step-by-step explanation:

there is no triples loll

soldi70 [24.7K]3 years ago
4 0

Answer:

triples

Step-by-step explanation:

ikkkkk its not triples lolllll

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Use the prism to answer the question. S in 2 in What is the surface area of the prism? O A 136 in2 B 192 in2 C 240 in2 D272 in2​
Vanyuwa [196]
Is there supposed to be a picture?? I see nothing im sorry. But i can help u cause this is just surface area, quite easy.
I will just give you the formula for surface area of a RECTANGULAR prism:
2 ( width x length + height x length + height x width) or just : 2 (wl + hl + hw)

Have a nice day
6 0
2 years ago
Read 2 more answers
Find the domains of the following functions:
larisa86 [58]
I think this is the answer to that,,, >y = 5x^2
3 0
3 years ago
Evaluate. 75-2(9-5)²+2³
Andreyy89
75-2(9-5)^2+2^3

First, solve the parentheses:

75-2(4)^2+2^3

Next, the exponential terms

75-2(16)+8

Solve the multiplication:

75-32+8

Add and subtract:

51

5 0
1 year ago
Sandra bought 120 square feet of carpet for a room in her new house. If the room is square, what is the length of each side of t
BARSIC [14]
Answer:
length of each side of the room is 2√30 which is approximately 10.9545 ft

Explanation:
The area of the square can be computed as follows:
Area = l²
where l is the length of the side

We are given that:
area = 120 ft²

Substitute with the area in the above equation and solve for l as follows:
area = l²
120 = l²
l = √120
l = 2√30 ft
This is approximately equal to 10.9545 ft

Hope this helps :)
3 0
3 years ago
Read 2 more answers
HELP THIS IS HARD SOMEONE pls
IrinaK [193]

Answer:

3rd option

Step-by-step explanation:

Since the centre of dilatation is at the origin then multiply the coordinates by \frac{1}{3}

K (- 3, 9 ) → K' (- 3(\frac{1}{3} ), 9(\frac{1}{3} ) ) → K' (- 1, 3 )

L (- 9, 0 ) → L' (- 9(\frac{1}{3} ), 0 (\frac{1}{3} ) ) → L' (- 3, 0 )

M (2, - 8 ) → M' (2 (\frac{1}{3} ), - 8 (\frac{1}{3} ) ) → M' ( \frac{2}{3} , - \frac{8}{3} )

N (6, 4 ) → N' (6 (\frac{1}{3} ) , 4 (\frac{1}{3} ) ) → N' ( 2, \frac{4}{3} )

7 0
3 years ago
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