Find the surface area of a right square pyramid with base edge length
2 feet and height 5 feet.
1 answer:
Answer:
24.4 sq. ft.
Step-by-step explanation:
Area of a right square pyramid is:
A = a^2 + 2(a)*square root of ((a^2/4) + b^2)
A = 4 + 4 (square root of ((4/4) + 25) = 4 + 4* square root of 26
A = 4 + 4*5.099
A = 4 + 20.396
A = 24.396 sq ft.
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