Write the equation of the first train: x = 12t
Write the equation of the second train: y = -20t+72, assuming the train one is at the origins when t = 0.
Now solve the equation: 12t=-20t+72,
32t = 72, then t = 2.25 hours. The two train meet after 2.25 hours.
Now the equation of the <span>pigeon is like this: x = 48t.
</span>Then for t = 2.25, we get
<span>The Hyde has flown 108 km when the trains meet.</span>
Write the equation of the second train: y = -20t+72, assuming the train one is at the origins when t = 0.
Now solve the equation: 12t=-20t+72,
32t = 72, then t = 2.25 hours. The two train meet after 2.25 hours.
Now the equation of the <span>pigeon is like this: x = 48t.
</span>Then for t = 2.25, we get
<span>The Hyde has flown 108 km when the trains meet.</span>
