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2 years ago

12

Does the temperature outside depend on the time of day, or does the time of day depend on the temperature outside? This may seem

like a silly question
ut to sketch a graph that represents this relationship, you first need to decide which axis will represent which quantity

1 answer:

Soloha48 [4]2 years ago

3 0

Temperature changes depending on the time of the day.

Step-by-step explanation:

You might be interested in

If I currently have a 77% in my course, and I have final that's worth 30%, how would a score of exactly 0% or 100% on the final

Neporo4naja [7]

Answer:

If you score a 0% on your exam, you get 53.9% as your overall grade
If you score 100% on your exam, you get 83.9% as your overall grade

====================================================

Explanation:

Your final is worth 30% of your grade, so the other 70% is what you've already done so far

The expression below

0.30x + 0.70*0.77

represents what your final grade would be in decimal form. We multiply the weights 0.30 and 0.70 with each of their corresponding grade value.

The x represents the decimal form of the final exam score.

------------

Let's say you get a 0% on the final. That would mean x = 0 and

0.30x + 0.70*0.77

0.30*0 + 0.70*0.77

0.539

So you'd end up with a 53.9% as the overall grade.

------------

Now let's say you get 100% on the final. We plug in x = 1 since it's the decimal form of 100%

So,

0.30x + 0.70*0.77

0.30*1 + 0.70*0.77

0.839

You would end up with a 83.9% as the overall grade.

4 0

3 years ago

Rena used the steps below to evaluate the

Yakvenalex [24]

Answer:

$1 \times 2 \times 3 \times 4$

6 0

1 year ago

Give an example of a function F(x) that is an antiderivative of f(x) = 9 cos(9x)+ 3x^2

liubo4ka [24]

We are integrating f(x) = 9cos(9x) + 3x²: $\int\ {9cos(9x)+3x^{2} } \, dx$

a) Apply the sum rule

$\int\9cos(9x)} \, dx +\int\ 3x^{2} } \, dx$

b) Calculate each antiderivative

<u>First integral</u>

$\int\ {9cos(9x)} \, dx$

1. Take out the constant

$9\int\ {cos(9x)} \, dx$

2. Apply u-substitution, where u is 9x

$9\int\ {cos(u)\frac{1}{9} } du$

3. Take out the constant (again)

$9*\frac{1}{9} \int{cos(u)} du$

4. Take the common integral of cos, which is sin

$9*\frac{1}{9}sin(u)}$

5. Substitute the original function back in for u and simplify $9*\frac{1}{9} sin(9x) = sin(9x)$

6. Always remember to add an arbitrary constant, C, at the end

$sin(9x) + C$

<u>Second integral</u>

$\int3x^{2} } \, dx$

1. Take out the constant

$3\int{x^{2} } \, dx$

2. Apply the power rule, $\int{x}^{a} \, dx =\frac{x^{a+1} }{a+1}$ , where <em>a</em> is your exponent

⇒ $3*\frac{x^{2+1} }{2+1} = x^{3}$

3. Add the arbitrary constant

$x^{3} + C$

c) Add the integrals

sin(9x) + C + x³ + C = sin(9x) + x³ + C

Notice the two arbitrary constants. Since we do not know what either constant is, we can combine them into one arbitrary constant.

<h3>Answer:</h3>

F(x) = sin(9x) + x³ + C

3 0

2 years ago

Read 2 more answers

. An Olympic runner completed a 100-meter race with a time of 12.5 seconds. What was her average speed?

svet-max [94.6K]

So you would do 100 divided by 12.5 and that equals 8. So the answer would be 8mph

5 0

2 years ago

X2-12x+20 anyone? help plz

Leto [7]

The answer is -10x+20

4 0

3 years ago