4x²+4x-35=0
factor: (2x+7)(2x-5)=0
2x+7=0, or 2x-5=0
2x=-7 or 2x=5
x=-3.5 or x=2.5
I don't see any rounding necessary in this case.
when you factor ax²+bx+c, you take the two factors of a and the two factors of c, one factor of a times one factor of c, the other factor of a times the other factors, the sum of the two products make b.
in this case, the factors of 4 is 2 and 2, the factors of -35 is -5 and 7. I line them up in the following way:
2 -5
2 7
then I multiple them diagonally, the top left 2 multiplying the bottom right 7=14, and the other 2 multiplying -5=-10, 14 and -10 make a sum of 4.
if you don't get the desired sum, switch the factors up and down till you have the right combination. Note: Do not switch left and right.
I hope this makes sense to you.
Answer:
5/12 or 15/36
Step-by-step explanation:
Since he rolls two dice, he has a total probability of 6 times 6 = 36. The pairs, that he could add up to primes are (1,1), (2,1) * 2 (since he can get 1,2 as well), (1,4) * 2, (2,3) * 2, (3,4) * 2, (5, 2) * 2, (6,1) * 2, (5, 6) * 2. This is 1 + 2 + 2 + 2 + 2 + 2 + 2 + 2, which is equal to 15. This is a total of 15/36 possible ways, which is also equal to 5/12.
Answer:
y=2x + 2
Step-by-step explanation:
Δy
----- =
= 
=2
Δx
y = mx + b
6 = 2(2) + b
6 = 4 + b
2 = b
Answer:
36? im pretty sure it's 36
