2 years ago

You don't have to answer if you don't want to lol, but you just gotta simplify.

Mathematics

2 answers:

Anna35 [415]2 years ago

7 0

12shshshsusuwhshwhsjsjs

saveliy_v [14]2 years ago

4 0

Answer:

question 8 is 178cmcubed I think

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Rewrite this standard form quadratic equation into vertex form by completing the square. Upload your work here to show your thin

Alex787 [66]

Solution :

Given the equation :

$y = x^2 - 6x+3$

$y=1(x^2 - 6x +n)+3$

$n = \left(\frac{b}{2}\right)^2$

$n = \left(\frac{6}{2}\right)^2$

n = 9

$y=1(x^2 - 6x +9-9)+3$

$y=1(x^2 - 6x +9)-9+3$

$y=1(x-3)^2- 6$

Therefore the vertex form of $y = x^2 - 6x+3$ is $y=1(x-3)^2- 6$ .

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3 years ago

Solve pls brainliest

luda_lava [24]

Answer:

0÷3= 0

0/5= 0

Step-by-step explanation:

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2 years ago

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Aloiza [94]

Answer:

Step-by-step explanation:

3/4

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3 years ago

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Lena [83]

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3 years ago

Hopefully this is better to answer. can you help? lol (';

solong [7]

Answer:

Step-by-step explanation:

1+1=2 and 2=2

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