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Mariana [72]
2 years ago
9

I NEED HELPPPPP PLEASE

Mathematics
1 answer:
vlada-n [284]2 years ago
4 0

Answer:

132, 390, 244, 492

Step-by-step explanation:

those are the answers in order

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Hey, I need help BAD!! I am doing PEMDAS. 7+(5times6)45+9<br><br><br> Please help me!! Thanks!
leonid [27]

Answer:1

<h2>1,366</h2>

Step-by-step explanation:

P - parenthsis

E - exponents

M - multiplication

D - division

A - addition

S - subtraction

<h3>STICK TO THE ORDER:</h3>

7 + 5 x (6 x 45) + 9 = 1,336 ( Not the pemdas order)

But,

<h3>7 + (5 x 6)45 + 9 = 1,366  is the correct order for using PEMDAS.</h3>
4 0
3 years ago
Use the Distributive Property to express 18 +24<br> 3(6+9)<br> 6 (3+4)<br> 6(2 + 5)<br> 9(2+3)
Nadusha1986 [10]
6(3+4) is the right answer because when you distribute you get 18+24.
Hope this helps!!
5 0
3 years ago
Read 2 more answers
I would appreciate some help with this!
olganol [36]
Circumference is
2\pi(r)
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5 0
3 years ago
Solve tan 10 - tan 50 +tan 70 with trigonometry.
Jobisdone [24]
Below is the solution, I hope it helps.

  <span>i) tan(70) - tan(50) = tan(60 + 10) - tan(60 - 10) 

= {tan(60) + tan(10)}/{1 - tan(60)*tan(10)} - {tan(60) - tan(10)}/{1 + tan(10)*tan(60)} 

ii) Taking LCM & simplifying with applying tan(60) = √3, the above simplifies to: 

= 8*tan(10)/{1 - 3*tan²(10)} 

iii) So tan(70) - tan(50) + tan(10) = 8*tan(10)/{1 - 3*tan²(10)} + tan(10) 

= [8*tan(10) + tan(10) - 3*tan³(10)]/{1 - 3*tan²(10)} 

= [9*tan(10) - 3*tan³(10)]/{1 - 3*tan²(10)} 

= 3 [3*tan(10) - tan³(10)]/{1 - 3*tan²(10)} 

= 3*tan(30) = 3*(1/√3) = √3 [Proved] 

[Since tan(3A) = {3*tan(A) - tan³(A)}/{1 - 3*tan²(A)}, 
{3*tan(10) - tan³(10)}/{1 - 3*tan²(10)} = tan(3*10) = tan(30)]</span>
7 0
3 years ago
-14= − 20 y − 7 x ; 10 y + 4 = 2x solve by elimination
tatiyna
The answer is (2,0)
............
7 0
3 years ago
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