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zhenek [66]
3 years ago
13

In math class help!!!!!

Mathematics
1 answer:
Pani-rosa [81]3 years ago
8 0

i need more than this

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75% of what equals 225?<br> What did you get for 10%, 20% , 30% , 40%, 50% ,60% and 70%?
Lesechka [4]
75% of 225 = 300.

10% = 30
20% = 60
30% = 90
40% = 120
50% = 150
60% = 180
70% = 210
80% = 240
90% = 270
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If you need an explanation, just ask.
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8 0
3 years ago
PLZ HELPPPP
Zolol [24]

Answer:

Step-by-step explanation:

3x-4<8

3x<12

x<4

2x+2>4

2x>2

>1

6 0
3 years ago
A pair of equations is shown below:
Lana71 [14]
Part A: To solve graphically we have to graph first by plotting the y-int which is -9 & -1. Than use the slops 7/1 & 3/1
part B: (2,5)
4 0
3 years ago
He cost, in millions of dollars, of building a three-story high school in new york state was estimated to be c(x) = 2.1 + 0.12x
ratelena [41]

Given cost function is

c(x) = 2.1 + 0.12x - 0.0001x^2 (20 ≤ x ≤ 400)

where x is the number of thousands of square feet

total revenue will be $0.2 million dollars per thousand square feet

Revenue is 0.2 millions per thousand square feet. we know x is the number of thousand of square feet

So R(x) = 0.2x

We know Profit = Revenue - Cost

P(x) = R(x) - C(x)

P(x) = 0.2x - (2.1 + 0.12x - 0.0001x^2)

P(x) = 0.2x - 2.1 - 0.12x + 0.0001x^2)

combine like terms

P(x) =-2.1 + 0.08x + 0.0001x^2

Profit function is

P(x) =0.0001x^2 + 0.08x - 2.1


5 0
3 years ago
During halftime of a basketball ​game, a sling shot launches​ T-shirts at the crowd. A​ T-shirt is launched from a height of 4 f
Sonbull [250]

Answer:

(a) The time the T-shirt takes to maximum height is 2 seconds

(b) The maximum height is 68 ft

(c) The range of the function that models the height of the T-shirt over time given above is 4 + 64\cdot t - 16 \cdot  t^{2}

Step-by-step explanation:

Here, we note that the general equation representing the height of the T-shirt as a function of time is

h = h_1 + u\cdot t - \frac{1}{2} \cdot g  \cdot  t^{2}

Where:

h = Height reached by T-shirt

t = Time of flight

u = Initial velocity = 64 ft/s

g = Acceleration due to gravity (negative because upward against gravity) = 32 ft/s²

h₁ = Initial height of T-shirt = 4 ft

(a) The maximum height can be found from the time to maximum height given as

v = u - gt

Where:

u = Initial velocity = 64 ft/s

v = Final upward velocity at maximum height = 0 m/s

g = 32 ft/s²

Therefore,

0 = 64 - 32·t

32·t = 64 and

t = 64/32 = 2 seconds

(b) Therefore, maximum height is then

h = 4 + 64\times 2 - \frac{1}{2} \times 32  \times  2^{2}

∴ h = 68 ft

The T-shirt is then caught 41 ft above the court on its way down

(c) The range of the function that models the height of the T-shirt over time given above is derived as

h = h_1 + u\cdot t - \frac{1}{2} \cdot g  \cdot  t^{2}

With u = 64 ft/s

g = 32 ft/s² and

h₁ = 4 ft

The equation becomes

h =4 + 64\cdot t - \frac{1}{2} \times 32  \cdot  t^{2} = 4 + 64\cdot t - 16 \cdot  t^{2}.

6 0
3 years ago
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