What time is number 12? Please help

T what point does the curve have maximum curvature? Y = 7ex (x, y) = what happens to the curvature as x → ∞? Κ(x) approaches as

Nookie1986 [14]

Formula for curvature for a well behaved curve y=f(x) is

K(x)= $\frac{|{y}''|}{[1+{y}'^2]^\frac{3}{2}}$

The given curve is y=7 $e^{x}$

${y}''=7e^{x}\\ {y}'=7e^{x}$

k(x)= $\frac{7e^{x}}{[{1+(7e^{x})^2}]^\frac{3}{2}}$

${k(x)}'=\frac{7(e^x)(1+49e^{2x})(49e^{2x}-\frac{1}{2})}{[1+49e^{2x}]^{3}}$

For Maxima or Minima

${k(x)}'=0$

$7(e^x)(1+49e^{2x})(98e^{2x}-1)=0$

→ $e^{x}=0∨ 1+49e^{2x}=0∨98e^{2x}-1=0$

$e^{x}=0 , ∧ 1+49e^{2x}=0$ [not possible ∵there exists no value of x satisfying these equation]

→ $98e^{2x}-1=0$

Solving this we get

x= $-\frac{1}{2}\ln{98}$

As you will evaluate ${k(x})}''$ <0 at x= $-\frac{1}{2}\ln98$

So this is the point of Maxima. we get y=7×1/√98=1/√2

(x,y)=[ $-\frac{1}{2}\ln98$ ,1/√2]

k(x)= $\lim_{x\to\infty } \frac{7e^{x}}{[{1+(7e^{x})^2}]^\frac{3}{2}}$

k(x)= $\frac{7}{\infty}$

k(x)=0

5 0

3 years ago

Show work please please

Bess [88]

Answer:

can you give a word problem and not just a picture

Step-by-step explanation:

3 0

3 years ago

Which expression is represented by the diagram? o -6-(-1) o -6-1 o -5-(-1) o -5-1

cupoosta [38]

Option A:

–6 – (–1)

Solution:

Minus symbol are given in the diagram.

There are 6 minus symbol in the diagram.

From that expression 1 minus symbol is cancelled.

To find which expression represents this situation:

Option A: –6 – (–1)

Total number of minus = –6

From this cancel one minus: –6 – (–1)

–6 – (–1) = –6 + 1 = –5

So, remaining minus are –5.

This is the correct answer.

Option B: –6 –1

–6 –1 = –7

But note that remaining 5 minus are only there in the diagram.

So, this is not correct answer.

Option C: –5 – (–1)

Totally 6 minus in the problem. But here only 5 minus are given.

So, this is not correct answer.

Option D: –5 –1

Totally 6 minus in the problem. But here only 5 minus are given.

So, this is not correct answer.

Hence –6 – (–1) is the correct expression which represented the diagram.

8 0

3 years ago

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Order these numbers from least to the greatest, 47/10,4.606,4+13/20,4.64

exis [7]

Answer:

From lowest to highest, the numbers would follow the following order:

1) 4.606, 2) 4.64, 3) 4 + 13/20, 4) 47/10.

Step-by-step explanation:

Given that the numbers 47/10, 4.606, 4 + 13/20 and 4.64 are presented, to order these from lowest to highest, the following calculations must be performed:

47/10 = 4.70

4,606

4 + 13/20 = 4 + 0.65 = 4.65

4.64

Therefore, from lowest to highest, the numbers would follow the following order:

1) 4.606, 2) 4.64, 3) 4 + 13/20, 4) 47/10.

6 0

3 years ago

A box contains 2 red marbles, 3 green marbles, and 3 blue marbles. if we choose a marble, then another marble without putting th

Bad White [126]

There are 7 marbles, including 3 green ones, so at the start, there is a 3/7 chance of getting a green marble.
Assuming you did get a green one, there are now 6 marbles left, with 2 blue marbles, so there is a 2/6 chance of taking a blue marble.
Given that both have to happen, you must multiply each probability, hence the total probability is 3/7 x 2/6, or a 1/7 chance.
Hope this helped

7 0

3 years ago

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