The correct comparison for Weeks 5-8 is higher than Week 1-4, hence, the job satisfaction for Week 5-8 is 17% higher.
<u>Job Satisfaction Score</u> :
- Week 1 = 3.50
- Week 2 = 3.40
- Week 3 = 3.30
- Week 4 = 3.60
- Week 5 = 4.20
- Week 6 = 4.00
- Week 7 = 4.10
- Week 8 = 3.90
<u>Job Satisfaction for week 1 - 4</u> :
- Week 1 + Week 2 + Week 3 + Week 4
- (3.50 + 3.40 + 3.30 + 3.60) = 13.80
<u>Job Satisfaction for Week 5 - 8</u> :
- Week 5 + Week 6 + Week 7 + Week 8
- (4.20 + 4.00 + 4.10 + 3.90) = 16.20
<u>Difference</u><u> between the two categories</u> :
[(Week 5 - 8) - (Week 1-4)] / Week 1-4] × 100%
(16.20 - 13.80) / 13.80 × 100%
(2.4 / 13.80) × 100%
0.1739 × 100%
= 17.39%
Therefore, the job satisfaction for Week 5 - 8 is about 17% higher than Week 1 - 4
Learn more :brainly.com/question/13218948
The slope-point formula:
We have (3, -5) and (-8, 4).
Substitute:
Step-by-step explanation:
Let the height above which the ball is released be H
This problem can be tackled using geometric progression.
The nth term of a Geometric progression is given by the above, where n is the term index, a is the first term and the sum for such a progression up to the Nth term is
To find the total distance travel one has to sum over up to n=3. But there is little subtle point here. For the first bounce ( n=1 ), the ball has only travel H and not 2H. For subsequent bounces ( n=2,3,4,5...... ), the distance travel is 2×(3/4)n×H
a=2H..........r=3/4
However we have to subtract H because up to the first bounce, the ball only travel H instead of 2H
Therefore the total distance travel up to the Nth bounce is
For N=3 one obtains
D=3.625H
What is the value of x in this diagram?
Please help
