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Ann [662]
3 years ago
7

Help Me! ASAP! What is the slope of the line?​

Mathematics
2 answers:
Sergeu [11.5K]3 years ago
8 0

Answer:

2

Step-by-step explanation:

The answer and explanation is in the picture.

Natalka [10]3 years ago
6 0

Answer:

slope is 2

Step-by-step explanation:

Hope this helps. Pls give brainliest.

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HELP! Whoever gets it right gets brainliest!!
aleksandrvk [35]

Answer:

D infitently Many

Step-by-step explanation:

A system of linear equations usually has a single solution, but sometimes it can have no solution (parallel lines) or infinite solutions (same line). This article reviews all three cases. One solution. A system of linear equations has one solution when the graphs intersect at a point.

6 0
3 years ago
PLEASE HELP URGENTTT
Margaret [11]

Answer: g^2+2g+1

Step-by-step explanation: Since she wants each side to be 1 inch larger, each side has a length of g+1. You need to find the area by squaring (g+1).

Write this as (g+1)(g+1). Use the FOIL method to get g^2+g+g+1. Simplify this to g^2+2g+1.

3 0
3 years ago
Read 2 more answers
Solve the equation: 5.1 - 7x = 9.1
bonufazy [111]

Answer:

Order summands

2

Subtract

5

.

1

5.1

5.1

from both sides of the equation

3

Simplify

4

Divide both sides of the equation by the same term

5

Simplify

Step-by-step explanation:

6 0
3 years ago
A bag of chocolates is labeled to contain 0.384 pounds of chocolates. The actual weight of the chocolates is 0.3798 pounds. Are
Marta_Voda [28]

Based on the information given the chocolates stated on the label is 0.0042-ounce lighter.

Weight:

Using this formula

Chocolate weight=Current weight-Actual weight

Where:

Current weight=0.384

Actual weight=0.3798

Let plug in the formula

Chocolate weight=0.384-0.3798

Chocolate weight=0.0042 ounce

In conclusion, the chocolates stated on the label are 0.0042-ounce lighter.

6 0
2 years ago
❊ Simplify :
DiKsa [7]

Answer:

See Below.

Step-by-step explanation:

Problem 1)

We want to simplify:

\displaystyle \frac{a+2}{a^2+a-2}+\frac{3}{a^2-1}

First, let's factor the denominators of each term. For the second term, we can use the difference of two squares. Hence:

\displaystyle =\frac{a+2}{(a+2)(a-1)}+\frac{3}{(a+1)(a-1)}

Now, create a common denominator. To do this, we can multiply the first term by (<em>a</em> + 1) and the second term by (<em>a</em> + 2). Hence:

\displaystyle =\frac{(a+2)(a+1)}{(a+2)(a-1)(a+1)}+\frac{3(a+2)}{(a+2)(a-1)(a+1)}

Add the fractions:

\displaystyle =\frac{(a+2)(a+1)+3(a+2)}{(a+2)(a-1)(a+1)}

Factor:

\displaystyle =\frac{(a+2)((a+1)+3)}{(a+2)(a-1)(a+1)}

Simplify:

\displaystyle =\frac{a+4}{(a-1)(a+1)}

We can expand. Therefore:

\displaystyle =\frac{a+4}{a^2-1}

Problem 2)

We want to simplify:

\displaystyle \frac{1}{(a-b)(b-c)}+\frac{1}{(c-b)(a-c)}

Again, let's create a common denominator. First, let's factor out a negative from the second term:

\displaystyle \begin{aligned} \displaystyle &= \frac{1}{(a-b)(b-c)}+\frac{1}{(-(b-c))(a-c)}\\\\&=\displaystyle \frac{1}{(a-b)(b-c)}-\frac{1}{(b-c)(a-c)}\\\end{aligned}

Now to create a common denominator, we can multiply the first term by (<em>a</em> - <em>c</em>) and the second term by (<em>a</em> - <em>b</em>). Hence:

\displaystyle =\frac{(a-c)}{(a-b)(b-c)(a-c)}-\frac{(a-b)}{(a-b)(b-c)(a-c)}

Subtract the fractions:

\displaystyle =\frac{(a-c)-(a-b)}{(a-b)(b-c)(a-c)}

Distribute and simplify:

\displaystyle =\frac{a-c-a+b}{(a-b)(b-c)(a-c)}=\frac{b-c}{(a-b)(b-c)(a-c)}

Cancel. Hence:

\displaystyle =\frac{1}{(a-b)(a-c)}

4 0
3 years ago
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