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False False true
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Answer: True
Explanation:
Yes, the given statement is true that a DFA is equivalent to NFA in terms of power. For any type of NFA we can easily build an equal DFA so, the NFA are not much powerful as compared to DFA. Both NFA and DFA are characterized by a similar type of class.
DFA is a special case of NFA and They both defined in the same class of language. Each condition in the DFA get summarized by all the condition that the NFA has itself.
The answer is An embedded chart
Answer:
<u>720</u> possible PIN can be generated.
Explanation:
To calculate different number of orders of digits to create password and PIN, we calculate permutation.
Permutation is a term that means the number of methods or ways in which different numbers, alphabets, characters and objects can arranged or organized. To calculate the permutation following formula will be used:
nPr = n!/(n-r)!
there P is permutation, n is number of digits that need to be organize, r is the size of subset (Number of digits a password contains)
So in question we need to calculate
P=?
where
n= 10 (0-9 means total 10 digits)
r= 3 (PIN Consist of three digits)
So by using formula
10P3 = 10!/(10-3)!
=10!/7!
= 10x9x8x7!/7!
= 10x9x8
= 720
