1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
jolli1 [7]
3 years ago
13

Please help me here: h t t p s : / / t i n y u r l . c o m / y t 7 r 3 y a m

Computers and Technology
1 answer:
AysviL [449]3 years ago
4 0

Why would you even be promoting this

You might be interested in
Consider the following general code for allowing access to a resource:
Margaret [11]

Answer:

a) The code allows access even when  IsAccessAllowed(...) method fails.

b) Either use If

(dwRet = ACCESS_ALLOWED)

or use

if (dwRet == NO_ERROR)

to avoid flaw

Explanation:

Lets first see what the code chunk does:

DWORD dwRet = IsAccessAllowed(...);

if (dwRet == ERROR_ACCESS_DENIED) {

// Security check failed.

// Inform user that access is denied.

} else {

// Security check OK.

}

In the given code, DWORD is basically a data type for double word type integers and this is defined in windows.h

So there is DWORD type variable dwRet that is assigned a method calls.

The method is IsAccessAllowed() which checks if the access is allowed to user.

if (dwRet == ERROR_ACCESS_DENIED) condition basically checks if the value of DWORD type variable dwRet is equal to ERROR_ACCESS_DENIED

If this condition evaluates to true then the security checks fails and user is informed via some message or action that the access is denied.  But when the if condition evaluates to false then the else part executes which allows access.

So basically this chunk of code checks if the error ERROR_ACCESS_DENIED is returned.

Now the flaw in this program is what if the method IsAccessAllowed() by any reason. The reasons can be system failure or the memory failure. In memory failure case for example, the system returns out of memory error. So this means that the error is not  ERROR_ACCESS_DENIED. Instead it is out of memory error. So in such a case the user is allowed access as the if condition evaluates to false and else part executes. So if any other error is produced due to some reason like mentioned above, then user has unrestricted access.

This shows that the doe should not check for the failure or rely on checking ERROR_ACCESS_DENIED to allow access but instead it should check for success. Code should only give access privilege if access is allowed successfully or no error is produced.

So to avoid this flaw the code is altered as:

DWORD dwRet = IsAccessAllowed(...);

If (dwRet = ACCESS_ALLOWED) {

//Security check OK.

} else {

//Security check failed.

//Inform user that access is denied.

}

This will only allow access if ACCESS_ALLOWED evaluates to true and success is checked instead of failure here

You can also alter the if condition as:

If (dwRet = No_Error)

or

If (dwRet = 0)

The above if conditions checks if the access is allowed or if no error is produced. Only then it will allowed access otherwise not. So the access check is a success is checked first and failure (for any reason). The user is allowed access only if there is no error otherwise user is not allowed access.

6 0
3 years ago
What effect does screen resolution have on how graphics are displayed?
posledela
The clearer the resolution screen is it is better seen through the graphics. Say you have a bad computer screen, well your graphics are going to be bad. The better and higher quality it is will be the better you can see your images.
7 0
4 years ago
In what year did alienware introduce alienfx lighting zones into their pc's?
ser-zykov [4K]
The answer to the question asked  above is 2006. 
<span>Alienware introduce alienfx lighting zones into their pc's on 2006.</span>

Hope my answer would be a great help for you.    If you have more questions feel free to ask here at Brainly.
8 0
3 years ago
Write a program that checks whether a positive number given by an input from the user is greater than 5 and less than 20 with ja
Alona [7]

Answer:

Program written in Java is as follows

See comments for explanations

import java.util.Scanner;

public class CheckRange {

public static void main (String [] args)

{

// This line allows the program accept user input

Scanner input = new Scanner(System.in);

//This line declares variable for user input

int num;

//This line prompts user for input

System.out.print("Number: ");

//This line gets user input

num = input.nextInt();

/* The following if statement checks if the user input is greater than 5 and less than 20 */

if (num > 5 && num <= 20)

{

/* This line is executed if the above condition is true */

System.out.print(num+" is greater than 5 and less than 20");

}

else

{

/*If the condition is not true, this line is executed*/

System.out.print(num+" is not within specified range");

}

// The if condition ends here

}

}

5 0
3 years ago
Aye yo, how do I get rid of an already placed end crystal? I thought it looked cool to build in my minecraft survival house, and
SpyIntel [72]

Answer:

they can be removed safely if they're immersed in water first.

Explanation:

8 0
3 years ago
Read 2 more answers
Other questions:
  • You should use _____ software for writing a letter.
    10·1 answer
  • HELPPP ASAPP
    8·2 answers
  • What file formats can you safely use in a video presentation
    14·1 answer
  • 7. When using find command in word we can search?
    7·1 answer
  • Which device assists with medical imaging? HELPPPP!!!!!!
    12·1 answer
  • What is the square root of 1600 and 36 ?​
    6·1 answer
  • I will mark brainliest
    9·1 answer
  • Ethan wants to change the font in his document. He should _____.
    8·1 answer
  • (Print distinct numbers) Write a program that reads in integers separated by a space in one line and displays distinct numbers i
    8·1 answer
  • With a(n) ____ you can arrive at a scene, acquire the data you need, and return to the lab as quickly as possible.
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!