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ra1l [238]
3 years ago
6

To bundle links together in order to improve bandwidth availability and redundancy, what protocol is used

Computers and Technology
1 answer:
Daniel [21]3 years ago
8 0

Answer:

Link Aggregation Control Protocol

Explanation:

Link Aggregation Control Protocol can be used to assist in the formation of port channel bundles of physical links.

Link Aggregation Control Protocol is an IEEE standard defined in IEEE 802.3ad. LACP lets devices send Link Aggregation Control Protocol Data Units (LACPDUs) to each other to establish a link aggregation connection.

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Answer:

normal margins will fit the most content on a page

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2 years ago
In Python write a program that reads a list of integers into a list as long as the integers are greater than zero, then outputs
stealth61 [152]

Answer:

l = []

while True:

 no = int(input())

 if no>0:

   l.append(no)

 else:

   break

print(1)

If this helped consider marking this answer as brainliest. Have a good day.

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2 years ago
__________ is a computer tool for evaluating the risk of exposure to wildfires.
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Answer:

The statement is true

Explanation:

5 0
2 years ago
Read 2 more answers
Computer system with a 32-bit logical address and 4k-byte page size. assume that each entry of a page table consists of 4bytes.
Annette [7]

The number of bits in the physical address is 26 bits. The number of entries in a page table is \mathbf{2^{20}} entries. The size of the page table in a one-level paging scheme is 4MB.

<h3>
What is paging in Operating System?</h3>

Paging is a storage method used in operating systems to recover activities as pages from secondary storage and place them in primary memory. The basic purpose of pagination is to separate each procedure into pages.

We are given the following parameters:

  • 32-bit logical address
  • Page size = 4 KB = \mathbf{2^{12} \ bytes }
  • Size of each Page table entry = 4 bytes

Suppose the system supports physical memory size = 64 MB = \mathbf{2^{26} \ bytes}

Thus, the number of bits in the physical address is computed as:

= \mathbf{log_2 \{Physical-memory-size\}}

=\mathbf{log_2(2^{26})}}

= 26 bits

The number of entries in a page table = logical address space size/page size

The number of entries in a page table \mathbf{= \dfrac{2^{32}}{2^{12}}}

\mathbf{=2^{20}} entries

In a one-level paging scheme, the size of the table is:

= entire no. of page entries × page table size

= \mathbf{2^{20}\times 4 \ bytes}

= 4 MB

b.

suppose that this system supports up to 2^30 bytes of physical memory.

  • The size of the page table will be the same as 4 MB due to the fact that the number of entries, as well as, the page table entry size is the same.

Since the size of the page table surpasses that of a single page. A page cannot include a whole page table. Therefore, the page table must be broken into parts to fit onto numerous pages, and an additional level of the page table is required to access this page table.

  • This is called the Multi-Level Paging system.

Therefore, we can conclude that the number of bits in the physical address is 26 bits, the number of entries in a page table is \mathbf{2^{20}} entries, and the size of the page table in a one-level paging scheme is 4MB.

Learn more about Paging in Operating System here:

brainly.com/question/17004314

#SPJ1

4 0
1 year ago
Aubrey is on a Windows machine. She wants to back up her Halloween pictures on an external hard drive. Which of the following ta
Leya [2.2K]

Answer:

no clu3 lol

Explanation:

I'm stupid hahaha

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