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4 years ago

The total lateral surface area and the total surface area.

Mathematics

2 answers:

rodikova [14]4 years ago

5 0

Answer:

624

Step-by-step explanation:

goldfiish [28.3K]4 years ago

3 0

The total lateral surface area
This is the area of the sides of the figure. In this case it will be the sum of the three rectangles.
(13) * (14) + (13) * (14) + (14) * (10) = 504yd ^ 2
the total surface area.
This is the surface area of the whole figure. In this case there are three rectangles and two triangles.
(13) * (14) + (13) * (14) + (14) * (10) + (1/2) * (10) * (12) + (1/2) * (10) * (12 ) = 624 yd ^ 2
the answer is
total lateral surface area: 504yd ^ 2
total surface area: 624 yd ^ 2

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The price of products may increase due to inflation and decrease due to depreciation. Marco is studying the change in the price

inn [45]

Answer:

Product A has a greater percentage change in price.

Step-by-step explanation:

Part A:

The price f product A, f (x) after x years is given by:

$f(x) = 0.69\cdot(1.03)^{x}$

After x = 0 years, the price of product A is:

$f(0) = 0.69\cdot(1.03)^{0}=0.69$

After x = 1 years, the price of product A is:

$f(1) = 0.69\cdot(1.03)^{1}=0.69\cdot (1+0.03)=0.69\cdot (1+3\%)$

After 1 year, the price of product A is 3% times more than the original price.

This means that after one year, the new price is 103% of the original price, which means the price product A is increasing by 3%.

Again after x = 2 years, the price of product A is:

$f(2) = 0.69\cdot(1.03)^{2}=[0.69\cdot (1+3\%)]\times (1.03)$

This implies that after 2 years, the price of product A is 103% of the price after year 1.

This implies that the price of product A is 3% more than the previous year.

Thus, the price of product A is increasing each year by 3%.

Part B:

The data for Product B is as follows:

Time (t) Price [f (t)]

1 10,100

2 10,201

3 10,303.01

4 10,406.04

Product B is clearly increasing in price.

Consider the changes in price of Product B in the following intervals of years:

Year 1 - Year 2:

Price in year 1 = $10,100

Price in Year 2 = $10,201

Compute the increase percentage as follows:

$\text{Increase}\%=\frac{10201-10100}{10100}=0.01=1\%$

Year 2 - Year 3:

Price in Year 2 = $10,201

Price in year 3 = $10,303.01

Compute the increase percentage as follows:

$\text{Increase}\%=\frac{10303.01-10201}{10201}=0.01=1\%$

Year 3 - Year 4

Price in year 3 = $10,303.01

Price in Year 4 = $10,406.04

Compute the increase percentage as follows:

$\text{Increase}\%=\frac{10,406.04-10303.01}{10303.01}=0.09999\approx 0.01=1\%$

It is quite clear that the price of product B increases by 1% each year.

Thus, Product A has a greater percentage change in price.

3 0

3 years ago

2. Write an equation in slope-intercept form that is PARALLEL to y = 2x - 2 that passes through the point (-3, 5).

Natalija [7]

Answer: y=2x+b

Step-by-step explanation:

If it is parallel, it has the same slope. So we have:

Y=2x+b

Use the point to find b

5=2(-3)+b

5=-6+b

Add 6 to both sides

11=b

Y=2x+11

4 0

3 years ago

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kolbaska11 [484]

2(2 - 2x) = 4

Distribute (multiply) 2 inside the parentheses.

4 - 4x = 4

Subtract 4 from both sides.

-4x = 0

DIvide both sides by -4.

x = 0

x is 0 because anything divided by 0 (0/-4) equals 0.

8 0

3 years ago

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AleksandrR [38]

Answer: 0 radians

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