Answer:
Tyler is correct. The temperature dropped at a rate of about 4° per hour between 4 and 6, while the temperature dropped at about 2.25° per hour between 6 and 10.
Edit: Explanation
The question is asking about which window of time had a <em>faster</em> decline in temperature, not a larger total change in temperature.
In a 2 hour timeframe, the temperature dropped 8°. (4-6 PM)
In a separate 4 hour timeframe, the temperature dropped 9°. (6-10 PM)
To find which window had a faster change in temp, I took the total temperature drop for each timeframe, then divided it by the number of hours each drop took.
8° / 2 = 4° per hour for 4-6 PM
9° / 4 = 2.25° per hour from 6-10 PM
Since the speed at which the temperature dropped per hour was greater from 4-6 PM than 6-10 PM, Tyler was correct.
Answer:
4a + 7 = SIMPLIFIED
4a = -7
a= -1.75 ANSWER OF EXPONENT IF NEEDED
Superficie total de un prisma
La fórmula general para el área de superficie total de un prisma recto es T. S. A. = ph + 2B donde p representa el perímetro de la base, h la altura del prisma y B el área de la base.
¡Espero que esto ayude!
Slope = Change in Y / change in X
Slope = (8 - 2) / (9-6)
Slope = 6 / 3
Slope = 2
