<em>AC bisects ∠BAD, => ∠BAC=∠CAD ..... (1)</em>
<em>thus in ΔABC and ΔADC, ∠ABC=∠ADC (given), </em>
<em> ∠BAC=∠CAD [from (1)],</em>
<em>AC (opposite side side of ∠ABC) = AC (opposite side side of ∠ADC), the common side between ΔABC and ΔADC</em>
<em>Hence, by AAS axiom, ΔABC ≅ ΔADC,</em>
<em>Therefore, BC (opposite side side of ∠BAC) = DC (opposite side side of ∠CAD), since (1)</em>
<em />
Hence, BC=DC proved.
A unicycle has 1 wheel. u unicycles have u wheels.
A bicycle has 2 wheels. b bicycles have 2b wheels.
In u unicycles and b bicycles, there are a total of
u + 2b wheels.
We are told there are 28 wheels, so u + 2b must equal 28.
The answer is choice C. u + 2b = 28
Answer:1493.1
Step-by-step explanation:
Answer:
2
Step-by-step explanation:
Answer:
D
Step-by-step explanation:
The rest you can elimate because of obvious inferring and reasoning so process of elimination
