Two non-congruent circles intersect and have a common chord 40 cm
1 answer:
Answer:
- 25 cm
Step-by-step explanation:
The chord and the segment between the centers form the diagonals of a kite with each pair of side being the radius of the circles.
As we know the long diagonal bisects the shorter one and they are perpendicular.
<u>Using Pythagorean, lets find the distance between the center of a greater circle and the chord:</u>
- 52² - (40/2)² = 2304 ⇒ √2304 = 48 cm
<u>The distance from the center of smaller circle and the chord is:</u>
- 63 - 48 = 15 cm
<u>Now using Pythagorean again, find the radius of the smaller circle:</u>
- 15² + (40/2)² = 625 ⇒ √625 = 25 cm
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Given:
Height of Isabelle = 62 inches
Shadow of Isabelle = 93 inches
Shadow of tree = 279 inches
To find:
The height of the tree.
Solution:
Let height of tree be x.
Ratio of height to shadow for Isabelle and tree are
The shadow of Isabelle and tree are proportional to their shadows. So, both ratios must be equal.
Multiply both sides by 279.
Therefore, the height of tree is 186 inches.
