Two non-congruent circles intersect and have a common chord 40 cm
1 answer:
Answer:
- 25 cm
Step-by-step explanation:
The chord and the segment between the centers form the diagonals of a kite with each pair of side being the radius of the circles.
As we know the long diagonal bisects the shorter one and they are perpendicular.
<u>Using Pythagorean, lets find the distance between the center of a greater circle and the chord:</u>
- 52² - (40/2)² = 2304 ⇒ √2304 = 48 cm
<u>The distance from the center of smaller circle and the chord is:</u>
- 63 - 48 = 15 cm
<u>Now using Pythagorean again, find the radius of the smaller circle:</u>
- 15² + (40/2)² = 625 ⇒ √625 = 25 cm
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