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jek_recluse [69]
3 years ago
11

Multiply and simplify: (4b - 3)(2b + 1)

Mathematics
1 answer:
xxMikexx [17]3 years ago
4 0
The answer is b= (-0.5 , 0.75)
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How to simplify please help
Luda [366]

Okay, the image is a little tough to see, but I believe it looks something like this:

(5² -10 / 17 - 3 * 4) -1

The first step [remember PEMDAS] is parentheses

Next comes Exponents:

(25 - 10 / 17 - 3 * 4) -1

Then Multiplication:

(25 - 10 / 17 - 12) - 1

Then Division [which we can't do yet since it isn't fully simplified], so we skip to Addition... nothing again, then subtraction.

(15 / 5) - 1

Then we can divide:

(3) - 1

Then subtract!

2

The answer to your problem is 2.

Hope that helps!

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kiruha [24]

Answer:

Part A) V(t)=-5,750t+101,250

Part B) \$55,250

Step-by-step explanation:

Part A) Express the value of the bulldozer, V, as a function of how many years old it is, t.

Let

V ----> the value of the bulldozer (dependent variable or output value)

t ----> the number of years (independent variable or input value)

we know that

The linear function in slope intercept form is equal to

V(t)=mt+b

we have the ordered pairs

(0,101,250) and (15,15,000)

Find the slope

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

substitute

m=\frac{15,000-101,250}{15-0}

m=-\$5,750\ per\ year ----> is negative because is a decreasing function

The value of b is the initial value

so

b=\$101,250

substitute

V(t)=-5,750t+101,250

Part B) The value of the bulldozer after 8 years is

For t=8 years

substitute the value of t in the linear equation

V(t)=-5,750(8)+101,250=\$55,250

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astra-53 [7]
Blackhole or supernova because of its mass.
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Butoxors [25]

Answer:it is no solution because the two lines don’t touch which means you can’t have points.

Step-by-step explanation:

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The graph of the line passes through the points (0,-2) and (6,0). What is the equation of the line?
valina [46]

\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{-2})\qquad (\stackrel{x_2}{6}~,~\stackrel{y_2}{0}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{0-(-2)}{6-0}\implies \cfrac{0+2}{6}\implies \cfrac{2}{6}\implies \cfrac{1}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-(-2)=\cfrac{1}{3}(x-0) \\\\\\ y+2=\cfrac{1}{3}x\implies y=\cfrac{1}{3}x-2

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