<u>Finding x:</u>
We know that the diagonals of a rhombus bisect its angles
So, since US is a diagonal of the given rhombus:
∠RUS = ∠TUS
10x - 23 = 3x + 19 [replacing the given values of the angles]
7x - 23 = 19 [subtracting 3x from both sides]
7x = 42 [adding 23 on both sides]
x = 6 [dividing both sides by 7]
<u>Finding ∠RUT:</u>
We can see that:
∠RUT = ∠RUS + ∠TUS
<em>Since we are given the values of ∠RUS and ∠TUS:</em>
∠RUT = (10x - 23) + (3x + 19)
∠RUT = 13x - 4
<em>We know that x = 6:</em>
∠RUT = 13(6)- 4
∠RUT = 74°
The slope between the points (x1,y1) and (x2,y2) is
slope=(y2-y1)/(x2-x1)
(0,6) and (5,-4)
x1=0
y1=6
x2=5
y2=-4
slope=(-4-6)/(5-0)=-10/5=-2
slope=-2
Answer:

Step-by-step explanation:
the unit of length is meter,
so, 80cm=0.8cm, 10cm=0.1m
the length of the rail=
=
Answer:
-1/3
Step-by-step explanation:
Taking two points on the graph (I took (0,9) and (6,7)
Slope=(y2-y1)/(x2-x1)
(7-9)/(6-0)=-2/6
=-1/3
The disk method will only involve a single integral. I've attached a sketch of the bounded region (in red) and one such disk made by revolving it around the y-axis.
Such a disk has radius x = 1/y and height/thickness ∆y, so that the volume of one such disk is
π (radius) (height) = π (1/y)² ∆y = π/y² ∆y
and the volume of a stack of n such disks is

where
is a point sampled from the interval [1, 5].
As we refine the solid by adding increasingly more, increasingly thinner disks, so that ∆y converges to 0, the sum converges to a definite integral that gives the exact volume V,

