Answer:
a=12 m/s²
Explanation:
Newton's second law of motion states that the acceleration of a body is directly proportional to the force applied and takes place in the direction of force.
This can be summarized as: F=ma, where m is the mass of the object on which force F acts. a is the acceleration due to the force applied.
12N= 1kg×a
a=12N/1kg
a=12m/s²
Explanation:
Given
Velocity v = 23.0m/s
Distance S = 3.45m
Required
Time it will take the skier to reach the ground;
Using the equation of motion;
S = ut + 1/2gt²
3.45 = 23t + 1/2(9.8)t²
3.45 = 23t + 4.9t²
4.9t²+23t-3.45 = 0
Factorize;
t = -23 ±√23²-4(4.9)(-3.45)/2(4.9)
t = -23 ±√529+67.62/9.8
t = -23±√596.62/9.8
t = -23±24.43/9.8
t = 1.43/9.8
t = 0.146 secs
Hence take the skier 0.146 secs to reach the ground.
b) Horizontal distance covered is the range;
Range = U√2H/g
Range = 23√2(3.45)/9.8
Range = 23√6.9/9.8
Range = 23√0.7041
Range = 23(0.8391)
Range = 19.29m
Hence the horizontal distance travelled in air is 19.29m
Answer: 0.57
Explanation:
Let's begin by explaining that two angles are complementary when they sum is :
Having this clear, let's find from the following trigonometric function:
Now that we have the value of , let's find :
This is the complement of angle
Then, the cosine of the complement is:
This is the answer
Answer:
v0 = 25 m/s
vf = 0 m/s
a = -9.80 m/s^2
change in x = 31.89m
but that's only 1/3 of the hight, so i time it by 3 to get 96m