<span>a. In the process of induction, metal objects are positive because electrons are pushed out of the object to the earth. The mass of the object decreases by an amount equal to the mass of the electrons leaving the metal object.</span>
b. <span>During the induction process, electrons are drawn from the earth to the object, so that the metal object becomes negative. <span>The mass of the object increases by an amount equal to the mass of "excess" electrons dragged onto the object.</span></span>
Answer:
Explanation:
given,
charge of two spherical drop = 0.1 nC
potential at the surface = 300 V
two drops merge to form a single drop
potential at the surface of new drop = ?
r = 0.003 m
volume =
=
= 2.612 × 10⁻⁷ m³
R = 0.00396 m
Answer:
v = 2.94 m/s
Explanation:
When the spring is compressed, its potential energy is equal to (1/2)kx^2, where k is the spring constant and x is the distance compressed. At this point there is no kinetic energy due to there being no movement, meaning the net energy in the system is (1/2)kx^2.
Once the spring leaves the system, it will be moving at a constant velocity v, if friction is ignored. At this time, its kinetic energy will be (1/2)mv^2. It won't have any spring potential energy, making the net energy (1/2)mv^2.
Because of the conservation of energy, these two values can be set equal to each other, since energy will not be gained or lost while the spring is decompressing. That means
(1/2)kx^2 = (1/2)mv^2
kx^2 = mv^2
v^2 = (kx^2)/m
v = sqrt((kx^2)/m)
v = x * sqrt(k/m)
v = 0.122 * sqrt(125/0.215) <--- units converted to m and kg
v = 2.94 m/s
Hi there!
We can use the following equation for constant velocity:
d = displacement (m)
v = velocity (m/s)
t = time (s)
Plug in the givens:
Change in Momentum = mv - mu.
u = 0, v = 10 m/s. Note ball accelerated from rest, so initial velocity = 0. u =0
Change in Momentum = mv - mu = 3*10 - 3*0 =30.
Change in Momentum = 30 kgm/s.